Electrical Engineering · updated 23 Oct 2026

Switchgear & Protection MCQ – 19 previous year questions with solutions

Every Switchgear & Protection question asked in GPSC DEE Electrical, GPSC AE Electrical, Supervisor Instructor, RRB JE and more — arranged topic by topic, with the exam and paper shown on each question.

19 PYQs4 topics6 papersFree PDF
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Protective Relays MCQs 9

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Protective Relays › Differential Protection (2)

Q1Hard
A three−phase transformer having a line voltage ratio of 400/33000 V is connected in the star-delta. The CTs on the 400V side have a CT ratio of 1000/5. What must be the ratio of CTs on the 33000 side?
View answer & solution
Correct answer: A. 7/5
Quick explanation

Transformer differential protection requires the CT secondary currents presented to the relay to compensate for the transformer ratio and phase-connection effects. Using the given 400/33 kV transformer and 1000/5 CT on the LV side, the matching HV-side CT ratio corresponds to the keyed 7/5 value.

ILV / IHV = VHV / VLV = 33000/400 = 82.5 Then include √3 CT-connection compensation for differential balance.
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Q2Moderate
The function of a differential relay is to protect equipment against ___________.
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Correct answer: C. internal faults
Quick explanation

C — Internal faults. A differential relay compares quantities entering and leaving the protected zone; they balance for external faults and differ only for faults inside the zone.

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Protective Relays › Directional Relay (1)

Q3Moderate
Which of the following characteristics distinguishes a directional relay from a non-directional relay?
View answer & solution
Correct answer: C. A directional relay responds to the direction of current flow.
Quick explanation

C — It responds to the direction of current flow. Using a voltage polarising quantity, a directional relay identifies whether fault current/power flows forward or reverse and trips only for one direction.

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Protective Relays › Distance Relay (1)

Q4Easy
Which relay is used for transmission line protection based on impedance measurement?
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Correct answer: B. Distance relay
Quick explanation

B — Distance relay. It measures the apparent impedance V/I at the relay point; since line impedance is proportional to length, it operates when a fault lies within its set reach.

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Protective Relays › Protective Relays (1)

Q5Hard
Consider the following statements with reference to Protective Relays:
1. The minimum relay coil current at which the relay operates is called pick-up value.
2. The pick-up value of a relay is 7.5 A and fault current is 30 A. Therefore its plug setting multiplier is 5.
3. An earth fault current is generally lesser than the short-circuit current.
4. Induction relays are used with both A.C. and D.C quantities.
Which of these statements are correct?
View answer & solution
Correct answer: D. 1 and 3 only
Quick explanation

Plug setting multiplier is the fault current divided by relay pickup current. PSM=I_fault/I_pickup=30/7.5=4, so the statement claiming 5 is numerically incorrect. Key relation: PSM=I_fault/I_pickup.

Exam focus: Calculate PSM numerically before selecting an option. Common trap: Induction-type relays are not used directly on DC quantities.

PSM=Ifault/Ipickup.
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Protective Relays › Protective System (1)

Q6Moderate
What is the main purpose of including a protective system in an electrical power system?
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Correct answer: C. To protect equipment from damage by isolating the faulted section and maintaining continuity of supply
Quick explanation

C — Protect equipment, isolate the faulted section and maintain supply continuity. Protection detects faults, disconnects only the faulted part and keeps the healthy system running.

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Protective Relays › Restricted Earth Fault (1)

Q7Hard
The neutral of the three phase 20 MVA, 11 kV alternator is earthed through a resistance of 5 ohms. The relay is set to operate when there is an out of balance current of 1.5 A. The CTs have a ratio of 100/5. What should be the minimum value of the earthing resistance to protect 90% of winding?
View answer & solution
Correct answer: B. 2.12 Ω
Quick explanation

First refer the relay setting through the CT ratio: 100/5 = 20, so a 1.5 A relay pickup corresponds to 30 A primary residual current. Restricted-earth-fault sensitivity is then related to the voltage available at the minimum protected winding point and the neutral earthing resistance. The official final key gives 2.12 Ω for the stated 90% protection condition.

CT ratio = 100/5 = 20 Ip = 1.5 × 20 = 30 A Vph = 11,000/√3
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Protective Relays › Voltage Differential Protection (1)

Q8Easy
A voltage differential relay operates when ___________.
View answer & solution
Correct answer: D. the voltage difference exceeds a set value.
Quick explanation

D — The voltage difference exceeds a set value. The relay continuously compares the voltages at two monitored points and operates when their difference crosses the setting.

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Protective Relays › Zones of Protection (1)

Q9Easy
In a zone protection system of a power network, what is the primary objective of a back-up protection scheme?
View answer & solution
Correct answer: C. To operate only when the primary relay fails to isolate a fault in its own zone
Quick explanation

C — To operate only when primary protection fails. Back-up protection is time-delayed so the primary relay clears the fault first with minimum isolation; back-up acts only if it fails.

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Circuit Breakers MCQs 5

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Circuit Breakers › Air Circuit Breaker (1)

Q10Easy
Consider the following statements regarding Air Circuit Breakers (ACBs) used in industrial LT panels:
1. They are primarily used for low-current domestic applications.
2. They provide protection against overcurrent, short circuits and earth faults.
3. The quenching of the arc takes place in static air at atmospheric pressure.
Which of the statements given above is/are correct?
View answer & solution
Correct answer: B. 2 and 3 only
Quick explanation

Air circuit breakers are LV switchgear devices used at high-current incomers/feeders, not small domestic branch circuits. Modern trip units provide overcurrent/short-circuit and often earth-fault protection. Key relation: ACB applications commonly include main LT switchboards and large feeders.

Exam focus: Domestic low-current circuits normally use MCB/RCBO class devices. Common trap: ACB does not mean compressed-air blast breaker in this LT-panel context.

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Circuit Breakers › Arc Phenomenon (1)

Q11Moderate
When the contacts of a circuit breaker begin to separate while carrying current, what mainly causes an electric arc to form?
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Correct answer: D. Ionisation of the air or medium between the separating contacts
Quick explanation

D — Ionisation of the medium between the separating contacts. As the gap opens, current is forced through a tiny gap with a very high field and temperature, ionising the medium so it conducts as an arc.

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Circuit Breakers › Circuit Breaker Ratings (1)

Q12Easy
What is meant by the breaking capacity of a circuit breaker?
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Correct answer: C. The maximum current it can safely interrupt
Quick explanation

C — The maximum current it can safely interrupt. Breaking capacity is the highest prospective fault current the breaker can interrupt at rated voltage under specified conditions (expressed in kA or MVA).

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Circuit Breakers › MCCB (1)

Q13Easy
Regarding MCCBs (Molded Case Circuit Breakers), consider the following:
1. They have adjustable trip settings for current and time delay.
2. They are typically rated for currents up to 2500A.
3. They are used for both switching and protection of circuits.
Which of the statements given above is/are correct?
View answer & solution
Correct answer: D. 1, 2 and 3
Quick explanation

MCCBs provide switching, isolation and overcurrent protection for higher-current circuits than typical MCBs. Many have adjustable long-time/instantaneous or electronic trip settings. Key relation: Trip settings must coordinate with cable ampacity and downstream protection.

Exam focus: MCCB trip adjustability is a major distinction from many small MCBs. Common trap: Device frame rating and actual trip setting are not the same thing.

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Circuit Breakers › SF₆ Circuit Breaker (1)

Q14Easy
Compared with air, which of the following properties does sulphur hexafluoride (SF₆) gas used in circuit breakers have?
View answer & solution
Correct answer: D. Higher dielectric strength
Quick explanation

D — Higher dielectric strength. SF₆ is highly electronegative: it captures free electrons, has about 2–3 times the dielectric strength of air and recovers strength quickly after current zero.

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Generator & Transformer Protection MCQs 4

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Generator & Transformer Protection › Alternator Overcurrent Protection (1)

Q15Easy
Overcurrent protection in alternators ensures which of the following?
View answer & solution
Correct answer: C. System stability and safety of the alternator
Quick explanation

C — System stability and safety of the alternator. Excess current from a fault or severe overload overheats the winding and creates damaging electromagnetic forces; overcurrent protection disconnects the machine in time.

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Q16Easy
What is the purpose of a Buchholz relay in transformer protection?
View answer & solution
Correct answer: A. To detect internal faults such as short circuits and arcing in oil
Quick explanation

A Buchholz relay is a gas- and oil-surge-operated relay on oil-immersed transformers with a conservator. It alarms on slow internal faults and trips on severe internal faults.

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Generator & Transformer Protection › Prime Mover Failure (1)

Q17Easy
To prevent an alternator from operating in motor mode due to prime mover failure, a/an __________ relay is used.
View answer & solution
Correct answer: A. Reverse Power
Quick explanation

A — Reverse Power relay. It detects active power flowing from the energized system into the alternator when the prime mover can no longer supply sufficient mechanical power.

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Generator & Transformer Protection › Stator Earth-Fault Protection (1)

Q18Moderate
Which protection is employed for generator rating from 1 MVA to 5 MVA?
View answer & solution
Correct answer: C. Balanced earth fault
Quick explanation

C — Balanced earth fault. This is the protection scheme associated with the 1–5 MVA generator range in the supplied paper.

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Fuses MCQs 1

Q19Easy
A protective device with high rupturing capacity can:
View answer & solution
Correct answer: D. Safely interrupt heavy fault currents without equipment damage occurrence
Quick explanation

Rupturing (breaking) capacity is the largest prospective short-circuit current a device can interrupt safely. It is a fault-interruption rating — it does not change regulation, inductance or insulation resistance.

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Switchgear & Protection MCQ FAQs

How many Switchgear & Protection MCQs are on SarkariResultOut?

19 previous year Switchgear & Protection questions across 4 topics, each with the exam it was asked in, the verified answer and a step-by-step solution.

Which exams asked these Switchgear & Protection questions?

Supervisor Instructor · Part B Technical · 2026; GPSC DEE Electrical · DEE Master paper · 2026; RRB JE · CBT 2 Electrical · Shift 1; GPSC AE Electrical · AE R&B · 2025 · Series M; GPSSB AAE Electrical · CBRT 2026 · Technical and more.

Can I download Switchgear & Protection MCQs as a PDF?

Yes. Tap “Download Switchgear & Protection PDF” — it is free after a quick sign-in and includes every answer and solution.