Electrical Engineering · updated 23 Oct 2026

Signals & Systems MCQ – 26 previous year questions with solutions

Every Signals & Systems question asked in GPSC DEE Electrical, GPSC AE Electrical — arranged topic by topic, with the exam and paper shown on each question.

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LTI Systems & Convolution MCQs 7

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LTI Systems & Convolution › Causality and Stability (1)

Q1Moderate
The impulse response of an LTI system which is continuous is H (t) = e−|t|. The system is ___________
View answer & solution
Correct answer: C. Stable but not causal
Quick explanation

h(t)=e^{-|t|} is nonzero for t<0, so the system is not causal. But ∫|h(t)|dt over all time is finite (=2), so the LTI system is BIBO stable. Therefore it is stable but not causal.

Causality: h(t)=0 for t<0 ∫_{−∞}^{∞}|h(t)|dt = 2∫₀^∞e^(−t)dt = 2 < ∞
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LTI Systems & Convolution › Convolution (1)

Q2Moderate
With respect to the mathematical properties of convolution in linear time-invariant (LTI) systems, consider the following statements:
1. The convolution operation between two signals satisfies the commutative property irrespective of signal type.
2. The associative property of convolution allows grouping of signals without affecting the final output.
3. Convolution distributes over addition, enabling decomposition of complex inputs into simpler components.
4. Convolution is applicable only to time-invariant systems and not to time-varying systems.
Which of the above statements is/are correct?
View answer & solution
Correct answer: B. 1, 2 and 3 only
Quick explanation

For an LTI system, output is the convolution of input and impulse response. Convolution is commutative, associative and distributive. Key relation: y=x*h; DT: y[n]=Σ x[k]h[n−k].

Exam focus: Flip, shift, multiply, sum. Common trap: Convolution usually increases finite-sequence length; it does not always reduce it.

y=x*h; DT: y[n]=Σ x[k]h[n−k].
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LTI Systems & Convolution › Correlation (1)

Q3Easy
The auto-correlation function of a rectangular pulse of duration T is
View answer & solution
Correct answer: D. A triangular pulse of duration 2T
Quick explanation

The autocorrelation of a rectangular pulse is triangular. As one pulse slides across the other, their overlap length decreases linearly with shift; for an original pulse duration T, nonzero overlap exists from −T to +T, giving total triangular duration 2T.

Rxx(τ)=T−|τ|, |τ|≤T =0, |τ|>T Support width = 2T
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LTI Systems & Convolution › Discrete-Time Convolution (1)

Q4Moderate
With respect to convolution in discrete-time systems, consider the following statements:
1. Convolution represents the output of an LTI system as a weighted sum of shifted impulse responses.
2. The graphical method of convolution involves time reversal and shifting of one signal.
3. Convolution operation always reduces the length of the output sequence.
4. Convolution is valid for both continuous-time and discrete-time signals.
Which of the above statements is/are correct?
View answer & solution
Correct answer: A. 1, 2 and 4 only
Quick explanation

Convolution is the bridge between an input signal and the impulse response of an LTI system. The time-reversal step arises because the kernel is h[n−k] or h(t−τ), not h[k−n]. Key relation: DT: y[n]=Σ_{k=−∞}^{∞}x[k]h[n−k]. CT: y(t)=∫x(τ)h(t−τ)dτ. Finite DT length: Ly=Lx+Lh−1.

Exam focus: Graphical convolution sequence: fold → shift → multiply → sum. Common trap: Confusing convolution with element-wise multiplication or assuming output length always decreases.

DT: y[n]=Σ_{k=−∞}^{∞}x[k]h[n−k]. CT: y(t)=∫x(τ)h(t−τ)dτ. Finite DT length: Ly=Lx+Lh−1.
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LTI Systems & Convolution › Eigenfunctions (1)

Q5Hard
A signal e^(−at) sin (ωt) is the input to a real linear time invariant system. Given K and ∅ are constants, the output of the system will be of the form Ke^(−bt) sin (vt + ∅). The correct statement among the following is __________
View answer & solution
Correct answer: C. b must be equal to a and v must be equal to ω
Quick explanation

A damped sinusoid is the imaginary part of a complex exponential e^{(-a+jω)t}. For an LTI system, a complex exponential is an eigenfunction: the system changes only its complex gain, not the exponential's pole. Therefore the output retains the same decay rate a and angular frequency ω; only magnitude and phase change.

s₀ = −a + jω y(t) = H(s₀)e^{s₀t} ⇒ b = a, v = ω
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LTI Systems & Convolution › Impulse Response (1)

Q6Moderate
With reference to impulse response of LTI systems, consider the following statements:
1. The impulse response completely characterizes an LTI system.
2. The output of an LTI system can be obtained by convolving input with impulse response.
3. For a given system, the impulse response is unique.
4. Impulse response concept is applicable only to discrete-time systems.
Which of the above statements is/are correct?
View answer & solution
Correct answer: B. 1, 2 and 3 only
Quick explanation

The impulse response uniquely characterizes an LTI system for a specified input-output relationship because any input can be decomposed into shifted impulses and the output follows by convolution. This concept applies in both continuous and discrete time. Key relation: y(t)=x(t)*h(t); y[n]=x[n]*h[n].

Exam focus: For LTI questions, think 'impulse response + convolution'. Common trap: Impulse response is not a discrete-time-only concept.

y(t)=x(t)*h(t); y[n]=x[n]*h[n].
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LTI Systems & Convolution › Stability (1)

Q7Moderate
With reference to stability of continuous-time LTI systems, consider the following statements:
1. A system is stable if all poles of its transfer function lie in the left half of the s-plane.
2. Inclusion of the imaginary axis in the ROC ensures bounded output for bounded input.
3. Absolute integrability of the impulse response guarantees system stability.
4. Every causal system is automatically stable.
Which of the above statements is/are correct?
View answer & solution
Correct answer: B. 1, 2 and 3 only
Quick explanation

The impulse response uniquely characterizes an LTI system for a specified input-output relationship because any input can be decomposed into shifted impulses and the output follows by convolution. This concept applies in both continuous and discrete time. Key relation: y(t)=x(t)*h(t); y[n]=x[n]*h[n].

Exam focus: For LTI questions, think 'impulse response + convolution'. Common trap: Impulse response is not a discrete-time-only concept.

y(t)=x(t)*h(t); y[n]=x[n]*h[n].
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Signals & Classification MCQs 6

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Signals & Classification › Elementary Sequences (1)

Q8Easy
Determine the discrete−time signal: x(n) = 1 for n ≥ 0 and x(n) = 0 for n < 0.
View answer & solution
Correct answer: D. Unit step sequence
Quick explanation

The sequence defined as 1 for n≥0 and 0 for n<0 is the discrete-time unit step u[n]. It switches from 0 to 1 at n=0 and remains at 1 thereafter.

u[n] = {1, n ≥ 0 δ[n] = u[n] − u[n−1]
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Signals & Classification › Energy and Power Signals (1)

Q9Moderate
With reference to the classification of signals based on energy and power considerations, consider the following statements:
1. An energy signal is one whose total energy is finite while its average power over an infinite duration is zero.
2. A power signal is characterized by finite average power but infinite total energy when integrated over time.
3. A periodic signal with non-zero amplitude always qualifies as an energy signal due to repetition.
4. A time-limited signal that exists only over a finite duration necessarily has finite energy.
Which of the above statements is/are correct?
View answer & solution
Correct answer: A. 1, 2 and 4 only
Quick explanation

Energy and power are mutually exclusive classifications for ordinary nonzero signals: an energy signal has finite total energy and zero average power, while a power signal has finite nonzero average power and infinite energy. A finite-duration bounded signal normally has finite energy. Key relation: E=∫|x(t)|²dt; P=lim(T→∞)(1/2T)∫_{−T}^T|x(t)|²dt.

Exam focus: Periodic nonzero → usually power signal, not energy signal. Common trap: Repetition does not make a periodic signal finite-energy.

E=∫|x(t)|²dt; P=lim(T→∞)(1/2T)∫_{−T}^T|x(t)|²dt.
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Signals & Classification › Impulse, Step and Ramp (1)

Q10Easy
What is the relation between the unit impulse function and the unit ramp function?
View answer & solution
Correct answer: C. δ(t) = d²r(t)/dt²
Quick explanation

The unit ramp r(t) differentiates to the unit step u(t), and differentiating once more gives the unit impulse δ(t). Therefore δ(t) = d²r(t)/dt².

r(t) = t u(t) dr(t)/dt = u(t) d²r(t)/dt² = δ(t)
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Signals & Classification › Monotonic Signals (1)

Q11Moderate
Which of the following signals is monotonic?
View answer & solution
Correct answer: C. x(t) = sin²(2t) + cos²(2t) − 2t
Quick explanation

A monotonic signal consistently moves in only one direction (non-increasing or non-decreasing) over its domain. Simplify each candidate and/or inspect its derivative; the keyed choice is the expression that reduces to a monotonic function.

sin²(2t) + cos²(2t) = 1 So x(t) = 1 − 2t dx/dt = −2 < 0
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Signals & Classification › Periodic and Aperiodic Signals (1)

Q12Easy
When is x(t) said to be non-periodic signal?
View answer & solution
Correct answer: C. If the equation x (t) = x (t + T) is satisfied for no values of T
Quick explanation

A continuous-time signal is periodic only if there exists at least one finite positive T such that x(t+T)=x(t) for all t. If no positive finite T satisfies that condition, the signal is non-periodic (aperiodic).

∃ T₀ > 0 such that x(t+T₀)=x(t) ∀t
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Signals & Classification › Periodicity and Energy (1)

Q13Moderate
Given the following statements:
Statement 1:A periodic signal cannot be anticausal.
Statement 2:An energy signal must be of finite duration.
Choose the correct option for the above statements
View answer & solution
Correct answer: A. Statement 1 is true, but statement 2 is false
Quick explanation

A nonzero periodic signal repeats indefinitely; if it were zero for all positive time as a purely anticausal signal, periodic repetition would force it to be zero everywhere. An energy signal, however, need not have finite duration—for example an exponentially decaying signal can extend indefinitely yet have finite energy. Hence statement 1 is true and statement 2 false: option A.

Energy E=∫|x(t)|²dt <∞
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System Properties MCQs 4

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System Properties › Causality and Stability (1)

Q14Moderate
Regarding the concepts of causality and stability in continuous-time systems, consider the following statements:
1. A causal system produces output that depends only on present and past input values, not future inputs.
2. A system is said to be BIBO stable if every bounded input produces a bounded output.
3. All causal systems are inherently stable due to their dependence on past inputs only.
4. For an LTI system, inclusion of the imaginary axis in the ROC of its Laplace transform implies stability.
Which of the above statements is/are correct?
View answer & solution
Correct answer: C. 1, 2 and 4 only
Quick explanation

The Laplace transform must be considered together with its region of convergence. For a rational LTI system, BIBO stability requires the ROC to include the jω axis; causality imposes a right-sided ROC for a causal rational system. Key relation: X(s)=∫x(t)e^(−st)dt; stability ⇒ jω axis lies in ROC.

Exam focus: Transform expression + ROC identifies the time signal. Common trap: Never place a pole inside the ROC.

X(s)=∫x(t)e^(−st)dt; stability ⇒ jω axis lies in ROC.
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System Properties › Difference Equations (1)

Q15Easy
With respect to discrete-time systems, consider the following statements:
1. Discrete-time signals are defined only at integer time instants.
2. Such systems are commonly implemented using digital processors.
3. Difference equations are used to describe discrete-time systems.
4. Discrete-time systems cannot be linear.
Which of the above statements is/are correct?
View answer & solution
Correct answer: C. 1, 2 and 3 only
Quick explanation

A discrete-time signal is defined at discrete indices, commonly integer n, and discrete-time systems are often implemented by digital processors. Linear constant-coefficient difference equations are a standard way to describe such systems. Key relation: Example LTI form: y[n]+a1y[n−1]=b0x[n]+b1x[n−1].

Exam focus: Time discreteness and system linearity are separate properties. Common trap: Do not assume a digital/discrete system must be nonlinear.

Example LTI form: y[n]+a1y[n−1]=b0x[n]+b1x[n−1].
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System Properties › Linearity (1)

Q16Moderate
Out of the following systems with input x(t) and output y(t), identify the linear system.
View answer & solution
Correct answer: B. dy/dt + 2t y(t) = t²x(t)
Quick explanation

A system is linear when input, output and output derivatives appear only to the first power and are not multiplied together; coefficients may still depend on time. In option B, dy/dt+2t y=t²x satisfies this condition. The other listed equations contain squared signal terms. Therefore option B is linear.

Linear form: a1(t)dy/dt+a0(t)y=b0(t)x
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System Properties › Stability (1)

Q17Moderate
For what values of k is the following system stable, y = (k² − 3k − 4)log(x) + sin(x)?
View answer & solution
Correct answer: D. k = 4, − 1
Quick explanation

The term multiplying log(x) can become unbounded as x approaches 0⁺, so for the system to avoid that unbounded contribution its coefficient must be zero. Solve k²−3k−4=0, giving k=4 or k=−1.

k² − 3k − 4 = 0 (k − 4)(k + 1)=0 k = 4 or −1
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Fourier Series MCQs 3

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Fourier Series › Convergence (1)

Q18Moderate
When is Fourier convergence theorem applicable?
View answer & solution
Correct answer: A. Infinite series limit
Quick explanation

Fourier convergence results determine the limiting value to which a Fourier series (an infinite trigonometric series) converges. Under the standard convergence conditions, the series converges to the function at continuity points and to the midpoint of a finite jump at discontinuities. In the wording of this MCQ, the applicable purpose is the limit of an infinite series.

S(t₀)=f(t₀) S(t₀)=[f(t₀⁻)+f(t₀⁺)]/2
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Fourier Series › Harmonics (1)

Q19Moderate
A periodic square wave is formed by rectangular pulses ranging from −1 to +1 and period = 2 units. The ratio of the power in the 7th harmonic to the power in the 5th harmonic for this waveform is equal to ____________
View answer & solution
Correct answer: B. 0.5
Quick explanation

For an ideal symmetric square wave, only odd harmonics are present and the nth harmonic amplitude is proportional to 1/n. Harmonic power is proportional to amplitude squared, so P7/P5=(5/7)²≈0.51, nearest to 0.5.

Vn ∝ 1/n (n odd) P₇/P₅ = (V₇/V₅)² = (5/7)² = 25/49 ≈ 0.510
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Fourier Series › Periodic Signals (1)

Q20Moderate
With reference to Fourier Series representation of periodic signals, consider the following statements:
1. Fourier Series decomposes a periodic signal into a sum of harmonically related sinusoids.
2. The coefficients of the Fourier Series depend on the fundamental period of the signal.
3. Fourier Series can directly represent non-periodic signals without modification.
4. Both exponential and trigonometric forms of Fourier Series are equivalent representations.
Which of the above statements is/are correct?
View answer & solution
Correct answer: C. 1, 2 and 4 only
Quick explanation

Fourier methods decompose signals into frequency components. Fourier series represents periodic signals as harmonically related sinusoids or equivalent complex exponentials; non-periodic signals are handled by Fourier transform rather than ordinary Fourier series. Key relation: Real even x(t) ⇒ X(ω) real and even.

Exam focus: Symmetry can eliminate sine/imaginary terms immediately. Common trap: Fourier series is fundamentally for periodic signals.

Real even x(t) ⇒ X(ω) real and even.
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Fourier Transform MCQs 2

Fourier Transform › Fourier Analysis (1)

Q21Easy
With reference to frequency-domain analysis, consider the following statements:
1. Frequency-domain representation simplifies analysis of LTI systems.
2. Convolution in time domain becomes multiplication in frequency domain.
3. Frequency-domain analysis is not applicable to non-periodic signals.
4. Filters are often designed using frequency response characteristics.
Which of the above statements is/are correct?
View answer & solution
Correct answer: B. 1, 2 and 4 only
Quick explanation

Periodic signals are naturally described by Fourier series, while non-periodic signals use Fourier transforms. For LTI systems, H(jω) directly shows how each sinusoidal frequency component is scaled and phase shifted. Key relation: y=x*h ⇔ Y(jω)=X(jω)H(jω).

Exam focus: Series for periodic, transform for non-periodic—both belong to frequency-domain analysis. Common trap: Thinking “frequency domain” means “periodic signals only”.

y=x*h ⇔ Y(jω)=X(jω)H(jω).
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Fourier Transform › Signal Symmetry (1)

Q22Moderate
For a real-valued even signal in time domain, consider the following statements:
1. The signal satisfies the condition x(t) = x(−t) for all time.
2. Its Fourier Transform is purely real-valued without any imaginary component.
3. The odd component of such a signal is identically zero.
4. The imaginary part of its Fourier Transform is an even function.
Which of the above statements is/are correct?
View answer & solution
Correct answer: A. 1, 2 and 3 only
Quick explanation

A real even time-domain signal has a real even Fourier transform and zero odd component. Fourier series represents periodic signals as harmonically related sinusoids or equivalent complex exponentials; non-periodic signals are handled by Fourier transform rather than ordinary Fourier series. Key relation: Real even x(t) ⇒ X(ω) real and even.

Exam focus: Symmetry can eliminate sine/imaginary terms immediately. Common trap: Fourier series is fundamentally for periodic signals.

Real even x(t) ⇒ X(ω) real and even.
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Sampling MCQs 2

Sampling › Aliasing (1)

Q23Moderate
With reference to aliasing in sampled signals, consider the following statements:
1. Aliasing occurs when higher frequency components overlap with lower frequencies after sampling.
2. It results in irreversible distortion in the reconstructed signal.
3. Anti-aliasing filters are used prior to sampling to limit bandwidth.
4. Aliasing is more prominent when the signal is oversampled.
Which of the above statements is/are correct?
View answer & solution
Correct answer: D. 1, 2 and 3 only
Quick explanation

The sampling theorem requires a band-limited signal to be sampled at at least twice its highest frequency for ideal reconstruction. Anti-aliasing filters limit input bandwidth before sampling, and ideal reconstruction uses a low-pass interpolation filter. Key relation: f_s≥2f_max; Nyquist rate=2f_max.

Exam focus: Filter before the ADC, not after aliasing has already occurred. Common trap: Oversampling reduces aliasing risk; it does not create aliasing.

fs≥2f_max; Nyquist rate=2f_max.
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Sampling › Sampling Theorem (1)

Q24Moderate
With reference to sampling and reconstruction of signals, consider the following statements:
1. The sampling frequency must be at least twice the maximum frequency component present in the signal.
2. Aliasing occurs when the sampling frequency is insufficient to capture the signal bandwidth.
3. Reconstruction of a continuous-time signal from its samples requires an ideal low-pass filter.
4. Increasing the sampling frequency beyond requirement leads to aliasing effects.
Which of the above statements is/are correct?
View answer & solution
Correct answer: D. 1, 2 and 3 only
Quick explanation

The sampling theorem requires a band-limited signal to be sampled at at least twice its highest frequency for ideal reconstruction. Anti-aliasing filters limit input bandwidth before sampling, and ideal reconstruction uses a low-pass interpolation filter. Key relation: f_s≥2f_max; Nyquist rate=2f_max.

Exam focus: Filter before the ADC, not after aliasing has already occurred. Common trap: Oversampling reduces aliasing risk; it does not create aliasing.

fs≥2f_max; Nyquist rate=2f_max.
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Laplace Transform MCQs 1

Laplace Transform › Region of Convergence (1)

Q25Moderate
With reference to the Laplace Transform and its region of convergence (ROC), consider the following statements:
1. The ROC of a Laplace Transform cannot include any poles of the system function.
2. The stability of a system can be inferred from the location of the ROC in the complex plane.
3. The same Laplace Transform expression can correspond to different time-domain signals depending on ROC.
4. The ROC always spans the entire complex plane irrespective of signal nature.
Which of the above statements is/are correct?
View answer & solution
Correct answer: B. 1, 2 and 3 only
Quick explanation

The Laplace transform must be considered together with its region of convergence. The ROC excludes poles, and the same algebraic transform can represent different time signals with different ROCs. Key relation: X(s)=∫x(t)e^(−st)dt; stability ⇒ jω axis lies in ROC.

Exam focus: Transform expression + ROC identifies the time signal. Common trap: Never place a pole inside the ROC.

X(s)=∫x(t)e^(−st)dt; stability ⇒ jω axis lies in ROC.
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Z-Transform MCQs 1

Z-Transform › Region of Convergence (1)

Q26Moderate
With respect to the Z-transform used in discrete-time signal analysis, consider the following statements:
1. The Z-transform serves as the discrete-time counterpart of the Laplace Transform.
2. The region of convergence in the Z-plane typically takes the form of a circular ring.
3. The ROC necessarily includes the poles of the system function.
4. For a discrete-time system to be stable, the unit circle must lie within the ROC.
Which of the above statements is/are correct?
View answer & solution
Correct answer: C. 1, 2 and 4 only
Quick explanation

The Z-transform is the discrete-time counterpart of the Laplace transform. For an LTI discrete-time system, BIBO stability requires the unit circle to lie in the ROC. Key relation: X(z)=Σx[n]z^(−n); stability ⇒ |z|=1 lies in ROC.

Exam focus: ROC position tells causality/stability information. Common trap: Poles are excluded from the ROC.

X(z)=Σx[n]z^(−n); stability ⇒ |z|=1 lies in ROC.
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Signals & Systems MCQ FAQs

How many Signals & Systems MCQs are on SarkariResultOut?

26 previous year Signals & Systems questions across 8 topics, each with the exam it was asked in, the verified answer and a step-by-step solution.

Which exams asked these Signals & Systems questions?

GPSC DEE Electrical · DEE Master paper · 2026; GPSC AE Electrical · AE R&B · 2025 · Series M; GPSC DEE Electrical · DEE Electrical · 2024.

Can I download Signals & Systems MCQs as a PDF?

Yes. Tap “Download Signals & Systems PDF” — it is free after a quick sign-in and includes every answer and solution.