Electrical Engineering › Signals & Systems

LTI Systems & Convolution MCQ [Free PDF] – 7 Objective Questions with Answers

Every LTI Systems & Convolution question asked in GPSC DEE Electrical, GPSC AE Electrical — solve, check instantly, then read the formula and exam tip.

7 PYQs7 subtopics2 examsUpdated 23 Oct 2026
Topic practice0/7✓ 0✗ 0

Causality and Stability (1)

Q1Moderate
The impulse response of an LTI system which is continuous is H (t) = e−|t|. The system is ___________
View answer & solution
Correct answer: C. Stable but not causal
Quick explanation

h(t)=e^{-|t|} is nonzero for t<0, so the system is not causal. But ∫|h(t)|dt over all time is finite (=2), so the LTI system is BIBO stable. Therefore it is stable but not causal.

Causality: h(t)=0 for t<0 ∫_{−∞}^{∞}|h(t)|dt = 2∫₀^∞e^(−t)dt = 2 < ∞
Verified · SRO editorial deskSolution page → Report

Convolution (1)

Q2Moderate
With respect to the mathematical properties of convolution in linear time-invariant (LTI) systems, consider the following statements:
1. The convolution operation between two signals satisfies the commutative property irrespective of signal type.
2. The associative property of convolution allows grouping of signals without affecting the final output.
3. Convolution distributes over addition, enabling decomposition of complex inputs into simpler components.
4. Convolution is applicable only to time-invariant systems and not to time-varying systems.
Which of the above statements is/are correct?
View answer & solution
Correct answer: B. 1, 2 and 3 only
Quick explanation

For an LTI system, output is the convolution of input and impulse response. Convolution is commutative, associative and distributive. Key relation: y=x*h; DT: y[n]=Σ x[k]h[n−k].

Exam focus: Flip, shift, multiply, sum. Common trap: Convolution usually increases finite-sequence length; it does not always reduce it.

y=x*h; DT: y[n]=Σ x[k]h[n−k].
Verified · SRO editorial deskSolution page → Report

Correlation (1)

Q3Easy
The auto-correlation function of a rectangular pulse of duration T is
View answer & solution
Correct answer: D. A triangular pulse of duration 2T
Quick explanation

The autocorrelation of a rectangular pulse is triangular. As one pulse slides across the other, their overlap length decreases linearly with shift; for an original pulse duration T, nonzero overlap exists from −T to +T, giving total triangular duration 2T.

Rxx(τ)=T−|τ|, |τ|≤T =0, |τ|>T Support width = 2T
Verified · SRO editorial deskSolution page → Report

Discrete-Time Convolution (1)

Q4Moderate
With respect to convolution in discrete-time systems, consider the following statements:
1. Convolution represents the output of an LTI system as a weighted sum of shifted impulse responses.
2. The graphical method of convolution involves time reversal and shifting of one signal.
3. Convolution operation always reduces the length of the output sequence.
4. Convolution is valid for both continuous-time and discrete-time signals.
Which of the above statements is/are correct?
View answer & solution
Correct answer: A. 1, 2 and 4 only
Quick explanation

Convolution is the bridge between an input signal and the impulse response of an LTI system. The time-reversal step arises because the kernel is h[n−k] or h(t−τ), not h[k−n]. Key relation: DT: y[n]=Σ_{k=−∞}^{∞}x[k]h[n−k]. CT: y(t)=∫x(τ)h(t−τ)dτ. Finite DT length: Ly=Lx+Lh−1.

Exam focus: Graphical convolution sequence: fold → shift → multiply → sum. Common trap: Confusing convolution with element-wise multiplication or assuming output length always decreases.

DT: y[n]=Σ_{k=−∞}^{∞}x[k]h[n−k]. CT: y(t)=∫x(τ)h(t−τ)dτ. Finite DT length: Ly=Lx+Lh−1.
Verified · SRO editorial deskSolution page → Report

Eigenfunctions (1)

Q5Hard
A signal e^(−at) sin (ωt) is the input to a real linear time invariant system. Given K and ∅ are constants, the output of the system will be of the form Ke^(−bt) sin (vt + ∅). The correct statement among the following is __________
View answer & solution
Correct answer: C. b must be equal to a and v must be equal to ω
Quick explanation

A damped sinusoid is the imaginary part of a complex exponential e^{(-a+jω)t}. For an LTI system, a complex exponential is an eigenfunction: the system changes only its complex gain, not the exponential's pole. Therefore the output retains the same decay rate a and angular frequency ω; only magnitude and phase change.

s₀ = −a + jω y(t) = H(s₀)e^{s₀t} ⇒ b = a, v = ω
Verified · SRO editorial deskSolution page → Report

Impulse Response (1)

Q6Moderate
With reference to impulse response of LTI systems, consider the following statements:
1. The impulse response completely characterizes an LTI system.
2. The output of an LTI system can be obtained by convolving input with impulse response.
3. For a given system, the impulse response is unique.
4. Impulse response concept is applicable only to discrete-time systems.
Which of the above statements is/are correct?
View answer & solution
Correct answer: B. 1, 2 and 3 only
Quick explanation

The impulse response uniquely characterizes an LTI system for a specified input-output relationship because any input can be decomposed into shifted impulses and the output follows by convolution. This concept applies in both continuous and discrete time. Key relation: y(t)=x(t)*h(t); y[n]=x[n]*h[n].

Exam focus: For LTI questions, think 'impulse response + convolution'. Common trap: Impulse response is not a discrete-time-only concept.

y(t)=x(t)*h(t); y[n]=x[n]*h[n].
Verified · SRO editorial deskSolution page → Report

Stability (1)

Q7Moderate
With reference to stability of continuous-time LTI systems, consider the following statements:
1. A system is stable if all poles of its transfer function lie in the left half of the s-plane.
2. Inclusion of the imaginary axis in the ROC ensures bounded output for bounded input.
3. Absolute integrability of the impulse response guarantees system stability.
4. Every causal system is automatically stable.
Which of the above statements is/are correct?
View answer & solution
Correct answer: B. 1, 2 and 3 only
Quick explanation

The impulse response uniquely characterizes an LTI system for a specified input-output relationship because any input can be decomposed into shifted impulses and the output follows by convolution. This concept applies in both continuous and discrete time. Key relation: y(t)=x(t)*h(t); y[n]=x[n]*h[n].

Exam focus: For LTI questions, think 'impulse response + convolution'. Common trap: Impulse response is not a discrete-time-only concept.

y(t)=x(t)*h(t); y[n]=x[n]*h[n].
Verified · SRO editorial deskSolution page → Report