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Sequential Circuits MCQ [Free PDF] – 11 Objective Questions with Answers

Every Sequential Circuits question asked in GPSC DEE Electrical, GPSC AE Electrical — solve, check instantly, then read the formula and exam tip.

11 PYQs8 subtopics2 examsUpdated 23 Oct 2026
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Shift Registers (3)

Q1Moderate
A bidirectional 4-bit shift register is storing the nibble 1110. Its input is LOW. The nibble 0111 is waiting to be entered on the serial data-input line. After two clock pulses, the shift register is storing ________
View answer & solution
Correct answer: C. 1011
Quick explanation

For the specified shifting operation, track the stored bits one clock at a time rather than trying to jump directly to the result. The serial input enters at the appropriate end and every existing bit shifts one position per pulse; applying two pulses produces the final nibble selected by the answer key.

One clock pulse → one-bit shift. Repeat the state update twice using the stated serial-input sequence.
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Q2Moderate
The group of bits 10110111 is serially shifted (rightmost bit first) into an 8-bit parallel output shift register with an initial state 11110000. After two clock pulses, the register contains ____________
View answer & solution
Correct answer: D. 11111100
Quick explanation

A serial-in/parallel-out register accepts one incoming bit per clock. With the rightmost bit transmitted first, perform two serial shifts from the stated initial register contents; the answer follows from those two state transitions.

new register = shifted(old register) + next serial bit
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Q3Easy
A 4-bit shift register that receives 4 bits of parallel data will shift to the ________ by ________ position for each clock pulse.
View answer & solution
Correct answer: A. Right, one
Quick explanation

A 4-bit shift register loaded in parallel still shifts one bit position for each clock pulse once placed in shift mode. Under the convention used in the question, it shifts one position to the right per clock.

1 clock pulse = 1 stage shift
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Counters (2)

Q4Easy
Consider the following statements regarding Counters:
1. Asynchronous counters experience cumulative propagation delay due to ripple effect, limiting their operating speed in high-frequency applications.
2. All synchronous counters are free from decoding glitches and hazards under all operating conditions.
3. Synchronous counters eliminate ripple delay by clocking all flip-flops simultaneously, thereby improving speed and reliability.
Which of the above statements is/are correct?
View answer & solution
Correct answer: C. 1 and 3 only
Quick explanation

Asynchronous or ripple counters clock each stage from the previous stage, so propagation delays accumulate. Synchronous counters clock all flip-flops together and are therefore faster, but combinational decoding can still exhibit hazards/glitches depending on implementation. Key relation: Ripple delay roughly accumulates with number of stages.

Exam focus: Synchronous eliminates ripple-clock delay, not every possible logic hazard. Common trap: Synchronous does not mean glitch-proof.

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Q5Easy
What is the maximum possible range of bit-count specifically in n-bit binary counter consisting of ‘n’ number of flip-flops?
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Correct answer: C. 0 to 2n − 1
Quick explanation

An n-bit binary counter has 2ⁿ distinct states. If it starts at 0, the highest count is therefore 2ⁿ − 1, giving the range 0 to 2ⁿ − 1.

Number of states = 2ⁿ Count range = 0 to (2ⁿ − 1)
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Cascaded Counters (1)

Q6Easy
A 12 MHz clock frequency is applied to a cascaded counter containing a modulus-5 counter, a modulus-8 counter and a modulus-10 counter. The lowest output frequency possible is ________
View answer & solution
Correct answer: C. 30 kHz
Quick explanation

Cascaded counters divide the clock by the product of their moduli. Here the total division factor is 5×8×10 = 400, so 12 MHz / 400 = 30 kHz.

Mtotal = 5 × 8 × 10 = 400 fout = 12 MHz / 400 = 30 kHz
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Flip-Flops (1)

Q7Easy
Consider the following statements regarding Flip Flops:
1. SR flip-flop has invalid state when both inputs are high causing undefined output.
2. JK flip-flop resolves this issue by toggling when both inputs are high.
3. D flip-flop eliminates race condition by using level triggering.
Which of the above statements is/are correct?
View answer & solution
Correct answer: D. 1 and 2 only
Quick explanation

Flip-flops and latches store state. In the basic active-high SR form, S=R=1 is forbidden/invalid. Key relation: JK with J=K=1 → toggle.

Exam focus: Race-around is associated especially with level-triggered JK at long clock pulses. Common trap: Do not credit level triggering itself with eliminating race-around.

JK with J=K=1 → toggle.
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Registers (1)

Q8Easy
Consider the following statements regarding Registers:
1. Registers are groups of flip-flops used to store multi-bit binary data and are widely used for temporary storage inside digital systems.
2. Shift registers allow serial as well as parallel data transfer depending on configuration and are used in data conversion applications.
3. Registers inherently perform arithmetic operations like addition and subtraction without additional combinational circuits.
Which of the above statements is/are correct?
View answer & solution
Correct answer: D. 1 and 2 only
Quick explanation

A register is a group of flip-flops used to store a multi-bit word. Shift-register configurations can move data serially or in parallel and are widely used for serial/parallel conversion and temporary storage. Key relation: An n-bit register typically uses n storage elements.

Exam focus: Storage/shift is the register's core job; arithmetic needs extra logic. Common trap: Do not treat a register itself as an adder.

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Ripple Counters (1)

Q9Easy
A 4-bit ripple counter consists of flip-flops, where each have a propagation delay from clock to Q output of 15 ns. For the counter to recycle from 1111 to 0000, it takes a total of ________
View answer & solution
Correct answer: D. 60 ns
Quick explanation

In an asynchronous ripple counter, the transition must propagate through successive flip-flops. With four flip-flops each having 15 ns clock-to-Q delay, the worst-case settling time is 4×15 = 60 ns.

ttotal = n·tpd = 4 × 15 ns = 60 ns
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Sequential Circuits (1)

Q10Easy
Consider the following statements regarding Sequential circuit:
1. Sequential circuits depend on both present inputs and previous states stored in memory elements.
2. Flip-flops and latches provide storage capability in such systems.
3. All sequential circuits are necessarily asynchronous in operation.
Which of the above statements is/are correct?
View answer & solution
Correct answer: A. 1 and 2 only
Quick explanation

Sequential circuits combine logic with memory, so outputs/state depend on present inputs and previous state. Flip-flops and latches provide storage. Key relation: x[k+1]=F(x[k],u[k]); y[k]=G(x[k],u[k]).

Exam focus: Look for state/memory before classifying a circuit as sequential. Common trap: Do not equate 'sequential' with 'asynchronous'.

x[k+1]=F(x[k],u[k]); y[k]=G(x[k],u[k]).
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Serial/Parallel Conversion (1)

Q11Easy
Which type of device may be used to interface a parallel data format with external equipment’s serial format?
View answer & solution
Correct answer: A. UART
Quick explanation

A UART is designed to interface parallel data used inside a digital system with asynchronous serial data used on an external communication link. It performs parallel-to-serial transmission and serial-to-parallel reception.

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