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EasyDeputy Executive Engineer (Electrical), Class-2, Sports Authority of Gujarat / Assistant Engineer (Electrical), Class-2,2026✓ Editorially verified
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A DC circuit consists of a resistor of 10 Ω connected across a 20 V supply.With reference to current and power, consider the following statements:1.The current flowing through the resistor is 2 A.2.The power dissipated in the resistor is 40 W.3.If resistance is doubled, current becomes 1 A.4.Power remains unchanged if resistance is doubled.Which of the above statements is/are correct?

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Answer & Explanation
Correct AnswerC. 1, 2 and 3 only

Quick Explanation

At fixed supply voltage, doubling resistance halves current and halves power because P=V²/R. Given V=20 V and R=10 Ω: I=V/R=2 A and P=VI=40 W. If R doubles to 20 Ω at the same 20 V, I=1 A and P=20 W. Key relation: I=V/R; P=VI=I²R=V²/R.

Exam focus: At fixed V, power varies inversely with R. Common trap: Do not assume power stays constant when resistance changes on a fixed-voltage source.

Formula / Key Relation

I=V/R; P=VI=I²R=V²/R.

Detailed Explanation

Correct Answer: C - 1, 2 and 3 only Quick Concept Explanation At fixed supply voltage, doubling resistance halves current and halves power because P=V²/R. Given V=20 V and R=10 Ω: I=V/R=2 A and P=VI=40 W. If R doubles to 20 Ω at the same 20 V, I=1 A and P=20 W. Key relation: I=V/R; P=VI=I²R=V²/R.Exam focus: At fixed V, power varies inversely with R. Common trap: Do not assume power stays constant when resistance changes on a fixed-voltage source. Statement-wise Verification Statement 1 - Correct.The current flowing through the resistor is 2 A.Given V=20 V and R=10 Ω: I=V/R=2…

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