PYQ
EasyDeputy Executive Engineer (Electrical), Class-2, Sports Authority of Gujarat / Assistant Engineer (Electrical), Class-2,2026✓ Editorially verified
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Two resistors of 6 Ω and 3 Ω are connected in parallel across 12 V supply. Then1.Equivalent resistance is 2 Ω.2.Total current is 6 A.3.Current through 3 Ω resistor is 4 A.4.Power consumed is 72 W.Which of the above statements is/are correct?

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Answer & Explanation
Correct AnswerD. All of the above

Quick Explanation

Equivalent resistance is found from reciprocal addition, total current is the sum of branch currents, and total real power is the sum of branch powers. For 6 Ω || 3 Ω, Req=(6×3)/(6+3)=2 Ω. Total current=12/2=6 A. Key relation: 1/R_eq=Σ(1/R_i); I_i=V/R_i; P_total=V I_total.

Exam focus: Solve branch currents first when the same supply voltage appears across every resistor. Common trap: Adding parallel resistances directly is incorrect.

Formula / Key Relation

1/Req=Σ(1/Ri); Ii=V/Ri; Ptotal=V Itotal.

Detailed Explanation

Correct Answer: D - All of the above Quick Concept Explanation Equivalent resistance is found from reciprocal addition, total current is the sum of branch currents, and total real power is the sum of branch powers. For 6 Ω || 3 Ω, Req=(6×3)/(6+3)=2 Ω. Total current=12/2=6 A. Key relation: 1/R_eq=Σ(1/R_i); I_i=V/R_i; P_total=V I_total.Exam focus: Solve branch currents first when the same supply voltage appears across every resistor. Common trap: Adding parallel resistances directly is incorrect. Statement-wise Verification Statement 1 - Correct.Equivalent resistance is 2 Ω.Equivalent resistance is found from reciprocal addition, total current is the sum of branch currents, and…

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