Two resistors of 6 Ω and 3 Ω are connected in parallel across 12 V supply. Then1.Equivalent resistance is 2 Ω.2.Total current is 6 A.3.Current through 3 Ω resistor is 4 A.4.Power consumed is 72 W.Which of the above statements is/are correct?
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Equivalent resistance is found from reciprocal addition, total current is the sum of branch currents, and total real power is the sum of branch powers. For 6 Ω || 3 Ω, Req=(6×3)/(6+3)=2 Ω. Total current=12/2=6 A. Key relation: 1/R_eq=Σ(1/R_i); I_i=V/R_i; P_total=V I_total.
Exam focus: Solve branch currents first when the same supply voltage appears across every resistor. Common trap: Adding parallel resistances directly is incorrect.
Formula / Key Relation
1/Req=Σ(1/Ri); Ii=V/Ri; Ptotal=V Itotal.
Detailed Explanation
Correct Answer: D - All of the above Quick Concept Explanation Equivalent resistance is found from reciprocal addition, total current is the sum of branch currents, and total real power is the sum of branch powers. For 6 Ω || 3 Ω, Req=(6×3)/(6+3)=2 Ω. Total current=12/2=6 A. Key relation: 1/R_eq=Σ(1/R_i); I_i=V/R_i; P_total=V I_total.Exam focus: Solve branch currents first when the same supply voltage appears across every resistor. Common trap: Adding parallel resistances directly is incorrect. Statement-wise Verification Statement 1 - Correct.Equivalent resistance is 2 Ω.Equivalent resistance is found from reciprocal addition, total current is the sum of branch currents, and…
Correct Answer: D - All of the above
Quick Concept Explanation
Equivalent resistance is found from reciprocal addition, total current is the sum of branch currents, and total real power is the sum of branch powers. For 6 Ω || 3 Ω, Req=(6×3)/(6+3)=2 Ω. Total current=12/2=6 A. Key relation: 1/R_eq=Σ(1/R_i); I_i=V/R_i; P_total=V I_total.
Exam focus: Solve branch currents first when the same supply voltage appears across every resistor. Common trap: Adding parallel resistances directly is incorrect.
Statement-wise Verification
Statement 1 - Correct. Equivalent resistance is 2 Ω. Equivalent resistance is found from reciprocal addition, total current is the sum of branch currents, and total real power is the sum of branch powers.
Statement 2 - Correct. Total current is 6 A. Total current=12/2=6 A.
Statement 3 - Correct. Current through 3 Ω resistor is 4 A. The 3 Ω branch current=12/3=4 A.
Statement 4 - Correct. Power consumed is 72 W. Total power=12×6=72 W.
Core Concept
Parallel branches share the same voltage. Equivalent resistance is found from reciprocal addition, total current is the sum of branch currents, and total real power is the sum of branch powers.
Formula / Key Relationship
1/R_eq=Σ(1/R_i); I_i=V/R_i; P_total=V I_total.
Step-by-Step Check
For 6 Ω || 3 Ω, Req=(6×3)/(6+3)=2 Ω. Total current=12/2=6 A. The 3 Ω branch current=12/3=4 A. Total power=12×6=72 W.
Why the Other Options Are Wrong
Option A is incorrect because it omits correct statement(s) 3, 4. Option B is incorrect because it omits correct statement(s) 4. Option C is incorrect because it omits correct statement(s) 1, 3.
Exam Shortcut / Approach
Solve branch currents first when the same supply voltage appears across every resistor.
Common Mistake
Adding parallel resistances directly is incorrect.
Quick Revision
Parallel Resistor Current and Power is linked with Parallel Resistance, DC Circuits and Basic Electrical Engineering. Solve branch currents first when the same supply voltage appears across every resistor.
Quick Trick
Solve branch currents first when the same supply voltage appears across every resistor.
Why Other Options Are Wrong
Option A is incorrect because it omits correct statement(s) 3, 4. Option B is incorrect because it omits correct statement(s) 4. Option C is incorrect because it omits correct statement(s) 1, 3.
Common Mistake
Adding parallel resistances directly is incorrect.
Exam Tip
Solve branch currents first when the same supply voltage appears across every resistor.
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