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AC Voltage Controllers MCQ [Free PDF] – 4 Objective Questions with Answers

Every AC Voltage Controllers question asked in GPSC DEE Electrical, GPSC AE Electrical — solve, check instantly, then read the formula and exam tip.

4 PYQs4 subtopics2 examsUpdated 23 Oct 2026
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AC Voltage Controller (1)

Q1Easy
Consider the following statements regarding AC voltage controller:
1. Controls RMS output voltage.
2. Uses phase angle control.
3. Works only with resistive load.
4. Used in light dimmers.
Which of the statements are correct?
View answer & solution
Correct answer: A. 1, 2 and 4 only
Quick explanation

Unlike an inverter, an AC voltage controller does not change AC to a new frequency; it controls the portion of each source cycle applied to the load. With phase control, delaying the firing angle reduces RMS output. Key relation: For a resistive single-phase phase-controlled load, Vrms depends on firing angle α; frequency at the load remains the source frequency.

Exam focus: AC controller → same frequency, variable RMS voltage. Common trap: Confusing an AC voltage controller with a frequency converter/inverter.

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Applications (1)

Q2Easy
The AC voltage controllers are used in __________ applications.
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Correct answer: B. Electric heating
Quick explanation

AC voltage controllers vary the rms AC voltage supplied to a load without changing the supply frequency. A classic application is resistive electric heating, where delivered power is smoothly controlled by phase-angle or integral-cycle control.

P = V_rms² / R
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Sequence Control (1)

Q3Moderate
In a N-stage sequence controller, each secondary is rated for __________
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Correct answer: C. Vs/n
Quick explanation

In an N-stage sequence controller, the supply voltage is divided across the staged secondary arrangement; each secondary is designed for a fraction of the total controlled voltage. The keyed relation is Vs/n per stage.

Voltage per equal stage = Vs / n
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Thyristor Ratings (1)

Q4Easy
A single−phase AC switch is used in between a 230 V source and load of 2 kW and 0.8 lagging power factor. Determine the rms current rating required by the SCR. Use the factor of safety = 2.
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Correct answer: C. 21.74 A
Quick explanation

The load current is I = P/(V·pf) = 2000/(230×0.8) ≈ 10.87 A. With a safety factor of 2, the required SCR rms current rating is about 21.74 A.

Iload = P/(V cosφ) = 2000/(230×0.8) = 10.87 A Irating = 2 × Iload = 21.74 A
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