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Resonance MCQ [Free PDF] – 6 Objective Questions with Answers

Every Resonance question asked in GPSC DEE Electrical, GPSC AE Electrical, Supervisor Instructor, GPSSB AAE Electrical — solve, check instantly, then read the formula and exam tip.

6 PYQs4 subtopics4 examsUpdated 23 Oct 2026
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Resonance (2)

Q1Moderate
Consider the following statements regarding Resonance in RLC Circuit:
1. In series resonance, impedance becomes minimum and current becomes maximum.
2. At resonance, inductive reactance equals capacitive reactance.
3. Power factor at resonance becomes unity.
4. In parallel resonance, impedance becomes minimum.
Which of the above statements is/are correct?
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Correct answer: C. 1, 2 and 3 only
Quick explanation

For a series RLC circuit, XL=XC at resonance, so the impedance is purely resistive and minimum, current is maximum, and power factor is unity. In an ideal parallel resonant circuit the input impedance is high, not minimum. Key relation: ω₀=1/√(LC); f₀=1/(2π√LC); at resonance XL=XC.

Exam focus: Series resonance: Z minimum, I maximum. Parallel resonance: input Z maximum (ideal case). Common trap: Reactive voltages can be large even though net reactive voltage is zero.

ω₀=1/√(LC); f₀=1/(2π√LC); at resonance XL=XC.
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Q2Hard
A 440 V, 50 Hz AC source supplies a series LCR circuit with a capacitor and a coil. If the coil has 100 mΩ resistance and 15 mH inductance, then at a resonance frequency of 50 Hz, the half power frequencies of the circuit are ______________
View answer & solution
Correct answer: A. 50.53 Hz, 49.57 Hz
Quick explanation

For a high-Q series RLC circuit, bandwidth is Δf = R/(2πL). With R=0.1 Ω and L=15 mH, Δf≈1.061 Hz. Half-power frequencies lie approximately symmetrically around 50 Hz, giving about 49.47 Hz and 50.53 Hz; the nearest option is 49.57 Hz and 50.53 Hz.

BW = R/(2πL) = 0.1/(2π×0.015)
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Series Resonance (2)

Q3Easy
Consider the following statements:
1. In a series RLC circuit at resonance, impedance is purely resistive.
2. Voltage across L and C individually can be greater than source voltage.
3. Power consumed at resonance is zero.
Which of the above statements is/are correct?
View answer & solution
Correct answer: A. 1 and 2 only
Quick explanation

Electrical resonance occurs when the net reactive effect cancels. For a series RLC circuit, XL=XC at resonance, so the impedance is purely resistive and minimum, current is maximum, and power factor is unity. Key relation: ω₀=1/√(LC); f₀=1/(2π√LC); at resonance XL=XC.

Exam focus: Series resonance: Z minimum, I maximum. Parallel resonance: input Z maximum (ideal case). Common trap: Reactive voltages can be large even though net reactive voltage is zero.

ω₀=1/√(LC); f₀=1/(2π√LC); at resonance XL=XC.
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Q4Moderate
When an AC voltage is applied to a series RLC circuit operating at resonance, how does the circuit behave?
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Correct answer: A. As a purely resistive circuit
Quick explanation

A — As a purely resistive circuit. At series resonance X_L = X_C and they cancel, so Z = R (minimum) and current is maximum and in phase with voltage.

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Quality Factor and Bandwidth (1)

Q5Easy
To obtain wide bandwidth, network is designed with which of the following?
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Correct answer: B. Low Q factor
Quick explanation

For a resonant network, bandwidth is inversely proportional to quality factor: BW = f₀/Q. Therefore a wider bandwidth requires a lower Q.

Q = f₀ / BW BW = f₀ / Q
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Series RLC Resonance (1)

Q6Moderate
Voltage magnification factor of a series resonance circuit is:
View answer & solution
Correct answer: B. Q = ωL/R
Quick explanation

B — Q = ωL/R, with ω evaluated at resonance (ω = ω₀). The quality factor equals the voltage across either reactive component divided by the supply voltage at series resonance.

ω₀ = 1/√(LC); f₀ = 1/(2π√(LC)); Q = VL/V = VC/V = ω₀L/R = 1/(ω₀CR).
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