एक वैध HOLD अनुरोध केवल किसके पूरा होने के बाद ही सुनिश्चित होता है?
उत्तर और चरणबद्ध हल
D — 34 क्लॉक चक्र और 80286 RESET। 80286 बस-टाइमिंग परिपाटी के अनुसार वैध HOLD अनुरोध निर्दिष्ट बस-चक्र क्रम पूरा होने और प्रोसेसर RESET अवस्था के बाद ही पहचाना जाता है।
विस्तृत हल (मूल भाषा में)
Concept & Reasoning
This is a device-specific timing/detail question rather than a general microprocessor principle. HOLD/HLDA arbitration is constrained so the processor does not abandon a bus operation mid-cycle.
How to Solve It in the Exam
Device-specific timing → preserve the source processor context.
Important Exam Point
Do not reuse 8086 or 8085 HOLD timing for 80286.
Quick Trick
Device-specific timing → preserve the source processor context.
Common Mistake
Treating any asynchronous HOLD assertion as immediately granting the bus.
A valid HOLD request is ascertained only after the completion of
Answer & step-by-step solution
Under the 80286 bus-timing convention used by the question, a valid HOLD request is recognized only after completion of the specified bus-cycle sequence with the processor state/reset condition shown in the correct option. The official final answer is the 34-clock, 80286 RESET condition.
Concept & Reasoning
This is a device-specific timing/detail question rather than a general microprocessor principle. HOLD/HLDA arbitration is constrained so the processor does not abandon a bus operation mid-cycle.
How to Solve It in the Exam
Device-specific timing → preserve the source processor context.
Important Exam Point
Do not reuse 8086 or 8085 HOLD timing for 80286.
Quick Trick
Device-specific timing → preserve the source processor context.
Common Mistake
Treating any asynchronous HOLD assertion as immediately granting the bus.
માન્ય HOLD વિનંતી ફક્ત શેના પૂર્ણ થયા પછી જ સુનિશ્ચિત થાય છે?
જવાબ અને પગલાવાર ઉકેલ
D — 34 ક્લોક ચક્ર અને 80286 RESET. 80286 બસ-ટાઇમિંગ પરંપરા મુજબ માન્ય HOLD વિનંતી નિર્દિષ્ટ બસ-ચક્ર ક્રમ પૂર્ણ થયા અને પ્રોસેસર RESET સ્થિતિ પછી જ ઓળખાય છે.
વિગતવાર ઉકેલ (મૂળ ભાષામાં)
Concept & Reasoning
This is a device-specific timing/detail question rather than a general microprocessor principle. HOLD/HLDA arbitration is constrained so the processor does not abandon a bus operation mid-cycle.
How to Solve It in the Exam
Device-specific timing → preserve the source processor context.
Important Exam Point
Do not reuse 8086 or 8085 HOLD timing for 80286.
Quick Trick
Device-specific timing → preserve the source processor context.
Common Mistake
Treating any asynchronous HOLD assertion as immediately granting the bus.
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