માન્ય HOLD વિનંતી ફક્ત શેના પૂર્ણ થયા પછી જ સુનિશ્ચિત થાય છે?
જવાબ અને પગલાવાર ઉકેલ
D — 34 ક્લોક ચક્ર અને 80286 RESET. 80286 બસ-ટાઇમિંગ પરંપરા મુજબ માન્ય HOLD વિનંતી નિર્દિષ્ટ બસ-ચક્ર ક્રમ પૂર્ણ થયા અને પ્રોસેસર RESET સ્થિતિ પછી જ ઓળખાય છે.
વિગતવાર ઉકેલ (મૂળ ભાષામાં)
Concept & Reasoning
This is a device-specific timing/detail question rather than a general microprocessor principle. HOLD/HLDA arbitration is constrained so the processor does not abandon a bus operation mid-cycle.
How to Solve It in the Exam
Device-specific timing → preserve the source processor context.
Important Exam Point
Do not reuse 8086 or 8085 HOLD timing for 80286.
Quick Trick
Device-specific timing → preserve the source processor context.
Common Mistake
Treating any asynchronous HOLD assertion as immediately granting the bus.
A valid HOLD request is ascertained only after the completion of
Answer & step-by-step solution
Under the 80286 bus-timing convention used by the question, a valid HOLD request is recognized only after completion of the specified bus-cycle sequence with the processor state/reset condition shown in the correct option. The official final answer is the 34-clock, 80286 RESET condition.
Concept & Reasoning
This is a device-specific timing/detail question rather than a general microprocessor principle. HOLD/HLDA arbitration is constrained so the processor does not abandon a bus operation mid-cycle.
How to Solve It in the Exam
Device-specific timing → preserve the source processor context.
Important Exam Point
Do not reuse 8086 or 8085 HOLD timing for 80286.
Quick Trick
Device-specific timing → preserve the source processor context.
Common Mistake
Treating any asynchronous HOLD assertion as immediately granting the bus.
एक वैध HOLD अनुरोध केवल किसके पूरा होने के बाद ही सुनिश्चित होता है?
उत्तर और चरणबद्ध हल
D — 34 क्लॉक चक्र और 80286 RESET। 80286 बस-टाइमिंग परिपाटी के अनुसार वैध HOLD अनुरोध निर्दिष्ट बस-चक्र क्रम पूरा होने और प्रोसेसर RESET अवस्था के बाद ही पहचाना जाता है।
विस्तृत हल (मूल भाषा में)
Concept & Reasoning
This is a device-specific timing/detail question rather than a general microprocessor principle. HOLD/HLDA arbitration is constrained so the processor does not abandon a bus operation mid-cycle.
How to Solve It in the Exam
Device-specific timing → preserve the source processor context.
Important Exam Point
Do not reuse 8086 or 8085 HOLD timing for 80286.
Quick Trick
Device-specific timing → preserve the source processor context.
Common Mistake
Treating any asynchronous HOLD assertion as immediately granting the bus.
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