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Maximum Demand from Daily Energy

The daily energy produced by a power generating station is 720 MWh at a load factor of 0.6. What is the maximum demand of the station?

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Answer & Explanation

Correct AnswerA. 50W

Quick Explanation

Load factor=average load/maximum demand. Daily average load is 720 MWh/24 h=30 MW. Therefore maximum demand=30/0.6=50 MW, which is option A.

Formula / Key Relation

Pavg=720/24=30MW; MD=Pavg/LF=30/0.6=50MW

Maximum Demand from Daily Energy explanatory diagram

Detailed Explanation

Correct Answer

A — 50 MW

Concept and Reasoning

Load factor=average load/maximum demand. Daily average load is 720 MWh/24 h=30 MW. Therefore maximum demand=30/0.6=50 MW, which is option A.

Calculation / Key Relation

Pavg=720/24=30MW

MD=Pavg/LF=30/0.6=50MW

Exam Takeaway

Energy per day divided by 24 gives average MW.

Common Mistake

Do not divide daily MWh directly by load factor without first converting to average MW.

Quick Trick

Energy per day divided by 24 gives average MW.

Common Mistake

Do not divide daily MWh directly by load factor without first converting to average MW.

Exam Tip

Energy per day divided by 24 gives average MW.

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Maximum Demand from Daily Energy

Quick Explanation

Formula / Key Relation

Detailed Explanation

Correct Answer

Concept and Reasoning

Calculation / Key Relation

Exam Takeaway

Common Mistake

Quick Trick

Common Mistake

Exam Tip

Previous Exam Appearances

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