If the zeroth condition is satisfied then, for execution, the JNZ instruction takes
Answer & step-by-step solution
JNZ tests the zero flag and branches when Z=0. The timing depends on whether the jump is taken; under the processor/timing convention intended by this question, when the 'zero condition' is satisfied the execution path takes four clock cycles, matching the final key.
Concept & Reasoning
Conditional-branch timing must be read together with the exact processor architecture because 8085, 8086 and later x86 devices use different timing units and instruction encodings. The conceptual rule remains: JNZ means 'jump if not zero', so Z=1 means the branch condition is false; only the fall-through path executes.
How to Solve It in the Exam
Decode the flag condition before recalling cycle counts.
Important Exam Point
Do not transfer timing numbers from one processor family to another.
Quick Trick
Decode the flag condition before recalling cycle counts.
Common Mistake
Reading JNZ as 'jump if zero'.
यदि शून्य (zero) शर्त संतुष्ट होती है, तो निष्पादन के लिए JNZ निर्देश लेता है
उत्तर और चरणबद्ध हल
D — 4 क्लॉक चक्र। JNZ ज़ीरो फ्लैग जाँचता है और Z=0 होने पर जंप करता है। जब 'शून्य शर्त' संतुष्ट हो, तो प्रश्न की टाइमिंग परिपाटी के अनुसार निष्पादन में चार क्लॉक चक्र लगते हैं।
विस्तृत हल (मूल भाषा में)
Concept & Reasoning
Conditional-branch timing must be read together with the exact processor architecture because 8085, 8086 and later x86 devices use different timing units and instruction encodings. The conceptual rule remains: JNZ means 'jump if not zero', so Z=1 means the branch condition is false; only the fall-through path executes.
How to Solve It in the Exam
Decode the flag condition before recalling cycle counts.
Important Exam Point
Do not transfer timing numbers from one processor family to another.
Quick Trick
Decode the flag condition before recalling cycle counts.
Common Mistake
Reading JNZ as 'jump if zero'.
જો શૂન્ય (zero) શરત સંતોષાય, તો અમલ માટે JNZ સૂચના લે છે
જવાબ અને પગલાવાર ઉકેલ
D — 4 ક્લોક ચક્ર. JNZ ઝીરો ફ્લેગ ચકાસે છે અને Z=0 હોય ત્યારે જમ્પ કરે છે. 'શૂન્ય શરત' સંતોષાય ત્યારે પ્રશ્નની ટાઇમિંગ પરંપરા મુજબ અમલમાં ચાર ક્લોક ચક્ર લાગે છે.
વિગતવાર ઉકેલ (મૂળ ભાષામાં)
Concept & Reasoning
Conditional-branch timing must be read together with the exact processor architecture because 8085, 8086 and later x86 devices use different timing units and instruction encodings. The conceptual rule remains: JNZ means 'jump if not zero', so Z=1 means the branch condition is false; only the fall-through path executes.
How to Solve It in the Exam
Decode the flag condition before recalling cycle counts.
Important Exam Point
Do not transfer timing numbers from one processor family to another.
Quick Trick
Decode the flag condition before recalling cycle counts.
Common Mistake
Reading JNZ as 'jump if zero'.
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