The continuity equation is a combination of which of the two laws?
Answer & step-by-step solution
The continuity equation follows by taking the divergence of the Ampère-Maxwell law and using Gauss' law. This yields ∇·J = -∂ρv/∂t.
Concept & Reasoning
Ampère-Maxwell law states ∇×H = J + ∂D/∂t. Taking divergence of both sides gives zero on the left because divergence of a curl is always zero. On the right, ∇·J + ∂(∇·D)/∂t = 0. Gauss' law gives ∇·D = ρv. Substituting produces ∇·J + ∂ρv/∂t = 0, the differential continuity equation expressing conservation of charge. Thus the two field laws used are Ampère-Maxwell and Gauss.
How to Solve It in the Exam
Continuity equation = divergence of Ampère-Maxwell + Gauss law.
Important Exam Point
Remember the vector identity ∇·(∇×H)=0.
Quick Trick
Continuity equation = divergence of Ampère-Maxwell + Gauss law.
Common Mistake
Ohm's law is not required to derive charge continuity.

सांतत्य समीकरण (continuity equation) किन दो नियमों का संयोजन है?
उत्तर और चरणबद्ध हल
एम्पियर-मैक्सवेल नियम का डाइवर्जेंस लेकर और गॉस के नियम का उपयोग कर सांतत्य समीकरण मिलता है: ∇·J = -∂ρv/∂t।
विस्तृत हल (मूल भाषा में)
Concept & Reasoning
Ampère-Maxwell law states ∇×H = J + ∂D/∂t. Taking divergence of both sides gives zero on the left because divergence of a curl is always zero. On the right, ∇·J + ∂(∇·D)/∂t = 0. Gauss' law gives ∇·D = ρv. Substituting produces ∇·J + ∂ρv/∂t = 0, the differential continuity equation expressing conservation of charge. Thus the two field laws used are Ampère-Maxwell and Gauss.
How to Solve It in the Exam
Continuity equation = divergence of Ampère-Maxwell + Gauss law.
Important Exam Point
Remember the vector identity ∇·(∇×H)=0.
Quick Trick
Continuity equation = divergence of Ampère-Maxwell + Gauss law.
Common Mistake
Ohm's law is not required to derive charge continuity.

સાતત્ય સમીકરણ (continuity equation) કયા બે નિયમોનું સંયોજન છે?
જવાબ અને પગલાવાર ઉકેલ
એમ્પિયર-મેક્સવેલ નિયમનું ડાઇવર્જન્સ લઈ અને ગૉસના નિયમનો ઉપયોગ કરતાં સાતત્ય સમીકરણ મળે છે: ∇·J = -∂ρv/∂t.
વિગતવાર ઉકેલ (મૂળ ભાષામાં)
Concept & Reasoning
Ampère-Maxwell law states ∇×H = J + ∂D/∂t. Taking divergence of both sides gives zero on the left because divergence of a curl is always zero. On the right, ∇·J + ∂(∇·D)/∂t = 0. Gauss' law gives ∇·D = ρv. Substituting produces ∇·J + ∂ρv/∂t = 0, the differential continuity equation expressing conservation of charge. Thus the two field laws used are Ampère-Maxwell and Gauss.
How to Solve It in the Exam
Continuity equation = divergence of Ampère-Maxwell + Gauss law.
Important Exam Point
Remember the vector identity ∇·(∇×H)=0.
Quick Trick
Continuity equation = divergence of Ampère-Maxwell + Gauss law.
Common Mistake
Ohm's law is not required to derive charge continuity.
