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Q145ModerateMaxwell's Equations

The continuity equation is a combination of which of the two laws?

Answer & step-by-step solution
Correct answer: B. Ampere law and Gauss law
Quick explanation

The continuity equation follows by taking the divergence of the Ampère-Maxwell law and using Gauss' law. This yields ∇·J = -∂ρv/∂t.

∇×H = J + ∂D/∂t 0 = ∇·J + ∂(∇·D)/∂t ∇·J = -∂ρv/∂t

Concept & Reasoning

Ampère-Maxwell law states ∇×H = J + ∂D/∂t. Taking divergence of both sides gives zero on the left because divergence of a curl is always zero. On the right, ∇·J + ∂(∇·D)/∂t = 0. Gauss' law gives ∇·D = ρv. Substituting produces ∇·J + ∂ρv/∂t = 0, the differential continuity equation expressing conservation of charge. Thus the two field laws used are Ampère-Maxwell and Gauss.

How to Solve It in the Exam

Continuity equation = divergence of Ampère-Maxwell + Gauss law.

Important Exam Point

Remember the vector identity ∇·(∇×H)=0.

Quick Trick

Continuity equation = divergence of Ampère-Maxwell + Gauss law.

Common Mistake

Ohm's law is not required to derive charge continuity.

Solution diagram – The continuity equation is a combination of which of the two laws?
Exam tipRemember the vector identity ∇·(∇×H)=0.
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