Consider the following statements regarding Dielectrics:
1. Dielectric materials reduce electric field within them due to polarization effects.
2. Relative permittivity is always greater than or equal to unity for dielectric materials.
3. Polarization results from alignment of dipoles within the material.
4. Dielectrics increase capacitance by increasing electric field strength.
Which of the above statements is/are correct?
Answer & step-by-step solution
Bound charges created by polarization oppose the applied field inside the material and increase capacitance for a fixed geometry. Relative permittivity is the ratio ε/ε0 and is at least unity for ordinary passive dielectrics in elementary electrostatics. Key relation: C=εA/d=ε_r ε₀A/d.
Exam focus: Higher permittivity raises capacitance; it does not do so by increasing the internal electric field. Common trap: Do not confuse increased capacitance with increased field strength.
Statement-wise Verification
- Statement 1 - Correct.
Dielectric materials reduce electric field within them due to polarization effects.
A dielectric polarizes in an electric field. - Statement 2 - Correct.
Relative permittivity is always greater than or equal to unity for dielectric materials.
Relative permittivity is the ratio ε/ε0 and is at least unity for ordinary passive dielectrics in elementary electrostatics. - Statement 3 - Correct.
Polarization results from alignment of dipoles within the material.
Bound charges created by polarization oppose the applied field inside the material and increase capacitance for a fixed geometry. - Statement 4 - Incorrect.
Dielectrics increase capacitance by increasing electric field strength.
A dielectric increases capacitance through higher permittivity/polarization; for fixed free charge it reduces the internal field
Core Concept
A dielectric polarizes in an electric field. Bound charges created by polarization oppose the applied field inside the material and increase capacitance for a fixed geometry. Relative permittivity is the ratio ε/ε0 and is at least unity for ordinary passive dielectrics in elementary electrostatics.
Formula / Key Relationship
C=εA/d=ε_r ε₀A/d.
Why the Other Options Are Wrong
Option A is incorrect because it omits correct statement(s) 1. Option B is incorrect because it includes incorrect statement(s) 4 and omits correct statement(s) 2, 3. Option D is incorrect because it includes incorrect statement(s) 4.
Exam Shortcut / Approach
Higher permittivity raises capacitance; it does not do so by increasing the internal electric field.
Common Mistake
Do not confuse increased capacitance with increased field strength.
Quick Revision
Permittivity Polarization and Capacitance is linked with Polarization, Dielectrics and Electromagnetic Fields. Higher permittivity raises capacitance; it does not do so by increasing the internal electric field.
परावैद्युत (Dielectrics) के संबंध में निम्नलिखित कथनों पर विचार कीजिए:
1. ध्रुवण प्रभाव के कारण परावैद्युत पदार्थ अपने भीतर विद्युत क्षेत्र घटाते हैं।
2. परावैद्युत पदार्थों का सापेक्ष परावैद्युतांक हमेशा एक के बराबर या उससे अधिक होता है।
3. ध्रुवण पदार्थ के भीतर द्विध्रुवों के संरेखण से होता है।
4. परावैद्युत विद्युत क्षेत्र की तीव्रता बढ़ाकर धारिता बढ़ाते हैं।
उपरोक्त में से कौन-सा/से कथन सही है/हैं?
उत्तर और चरणबद्ध हल
ध्रुवण से बने बद्ध आवेश पदार्थ के भीतर लागू क्षेत्र का विरोध करते हैं और निश्चित ज्यामिति में धारिता बढ़ाते हैं। सापेक्ष परावैद्युतांक ε/ε0 सामान्य निष्क्रिय परावैद्युत के लिए कम से कम 1 है। मुख्य संबंध: C=ε_r ε₀A/d।
परीक्षा फोकस: अधिक परावैद्युतांक धारिता बढ़ाता है, आंतरिक क्षेत्र बढ़ाकर नहीं।
विस्तृत हल (मूल भाषा में)
Statement-wise Verification
- Statement 1 - Correct.
Dielectric materials reduce electric field within them due to polarization effects.
A dielectric polarizes in an electric field. - Statement 2 - Correct.
Relative permittivity is always greater than or equal to unity for dielectric materials.
Relative permittivity is the ratio ε/ε0 and is at least unity for ordinary passive dielectrics in elementary electrostatics. - Statement 3 - Correct.
Polarization results from alignment of dipoles within the material.
Bound charges created by polarization oppose the applied field inside the material and increase capacitance for a fixed geometry. - Statement 4 - Incorrect.
Dielectrics increase capacitance by increasing electric field strength.
A dielectric increases capacitance through higher permittivity/polarization; for fixed free charge it reduces the internal field
Core Concept
A dielectric polarizes in an electric field. Bound charges created by polarization oppose the applied field inside the material and increase capacitance for a fixed geometry. Relative permittivity is the ratio ε/ε0 and is at least unity for ordinary passive dielectrics in elementary electrostatics.
Formula / Key Relationship
C=εA/d=ε_r ε₀A/d.
Why the Other Options Are Wrong
Option A is incorrect because it omits correct statement(s) 1. Option B is incorrect because it includes incorrect statement(s) 4 and omits correct statement(s) 2, 3. Option D is incorrect because it includes incorrect statement(s) 4.
Exam Shortcut / Approach
Higher permittivity raises capacitance; it does not do so by increasing the internal electric field.
Common Mistake
Do not confuse increased capacitance with increased field strength.
Quick Revision
Permittivity Polarization and Capacitance is linked with Polarization, Dielectrics and Electromagnetic Fields. Higher permittivity raises capacitance; it does not do so by increasing the internal electric field.
પરાવૈદ્યુત (Dielectrics) સંબંધિત નીચેના વિધાનો ધ્યાનમાં લો:
1. ધ્રુવીભવન અસરને કારણે પરાવૈદ્યુત પદાર્થો પોતાની અંદર વિદ્યુત ક્ષેત્ર ઘટાડે છે.
2. પરાવૈદ્યુત પદાર્થોનો સાપેક્ષ પરાવૈદ્યુતાંક હંમેશા એક બરાબર કે તેથી વધુ હોય છે.
3. ધ્રુવીભવન પદાર્થની અંદર દ્વિધ્રુવોની ગોઠવણથી થાય છે.
4. પરાવૈદ્યુત વિદ્યુત ક્ષેત્રની તીવ્રતા વધારીને કેપેસિટન્સ વધારે છે.
ઉપરોક્તમાંથી કયું/કયા વિધાન સાચું/સાચા છે?
જવાબ અને પગલાવાર ઉકેલ
ધ્રુવીભવનથી બનતા બદ્ધ વિદ્યુતભાર પદાર્થની અંદર લાગુ ક્ષેત્રનો વિરોધ કરે છે અને નિશ્ચિત ભૂમિતિમાં કેપેસિટન્સ વધારે છે. સાપેક્ષ પરાવૈદ્યુતાંક ε/ε0 સામાન્ય નિષ્ક્રિય પરાવૈદ્યુત માટે ઓછામાં ઓછો 1 છે. મુખ્ય સંબંધ: C=ε_r ε₀A/d.
પરીક્ષા મુદ્દો: વધુ પરાવૈદ્યુતાંક કેપેસિટન્સ વધારે છે, આંતરિક ક્ષેત્ર વધારીને નહીં.
વિગતવાર ઉકેલ (મૂળ ભાષામાં)
Statement-wise Verification
- Statement 1 - Correct.
Dielectric materials reduce electric field within them due to polarization effects.
A dielectric polarizes in an electric field. - Statement 2 - Correct.
Relative permittivity is always greater than or equal to unity for dielectric materials.
Relative permittivity is the ratio ε/ε0 and is at least unity for ordinary passive dielectrics in elementary electrostatics. - Statement 3 - Correct.
Polarization results from alignment of dipoles within the material.
Bound charges created by polarization oppose the applied field inside the material and increase capacitance for a fixed geometry. - Statement 4 - Incorrect.
Dielectrics increase capacitance by increasing electric field strength.
A dielectric increases capacitance through higher permittivity/polarization; for fixed free charge it reduces the internal field
Core Concept
A dielectric polarizes in an electric field. Bound charges created by polarization oppose the applied field inside the material and increase capacitance for a fixed geometry. Relative permittivity is the ratio ε/ε0 and is at least unity for ordinary passive dielectrics in elementary electrostatics.
Formula / Key Relationship
C=εA/d=ε_r ε₀A/d.
Why the Other Options Are Wrong
Option A is incorrect because it omits correct statement(s) 1. Option B is incorrect because it includes incorrect statement(s) 4 and omits correct statement(s) 2, 3. Option D is incorrect because it includes incorrect statement(s) 4.
Exam Shortcut / Approach
Higher permittivity raises capacitance; it does not do so by increasing the internal electric field.
Common Mistake
Do not confuse increased capacitance with increased field strength.
Quick Revision
Permittivity Polarization and Capacitance is linked with Polarization, Dielectrics and Electromagnetic Fields. Higher permittivity raises capacitance; it does not do so by increasing the internal electric field.
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