Final Value from Y(s)
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Apply the final-value theorem: y(∞)=lim_{s→0}sY(s). With Y(s)=10(2s+3)/[s(s²+2s+5)], the limit is 10×3/5=6. The poles of sY(s) are in the left half-plane, so the theorem is applicable. Hence option C.

Cancel the integrator through sY(s), then check stability of the remaining poles.
Do not substitute s=0 directly into Y(s); the final-value theorem uses sY(s).
Cancel the integrator through sY(s), then check stability of the remaining poles.