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Electromagnetic Waves MCQ [Free PDF] – 5 Objective Questions with Answers

Every Electromagnetic Waves question asked in GPSC DEE Electrical, GPSC AE Electrical — solve, check instantly, then read the formula and exam tip.

5 PYQs5 subtopics2 examsUpdated 23 Oct 2026
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Distributed-Parameter Lines (1)

Q1Moderate
Consider the following statements regarding Transmission Lines:
1. Transmission lines exhibit distributed parameters such as resistance, inductance, capacitance and conductance.
2. Characteristic impedance is independent of line length.
3. Reflection occurs when load impedance does not match line impedance.
4. Standing waves are formed due to reflections along the line.
Which of the above statements is/are correct?
View answer & solution
Correct answer: D. All of the above
Quick explanation

Its characteristic impedance is set by those per-unit-length parameters and frequency, not by line length. A mismatch between load and characteristic impedance causes reflected waves and standing-wave patterns. Key relation: Z₀=√((R+jωL)/(G+jωC)); Γ=(Z_L−Z₀)/(Z_L+Z₀).

Exam focus: Match ZL to Z0 to eliminate reflection. Common trap: Characteristic impedance is not the same as total line impedance.

Z₀=√((R+jωL)/(G+jωC)); Γ=(ZL−Z₀)/(ZL+Z₀).
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Field Power Density (1)

Q2Moderate
Find the power, given energy E = 2J and current density J = x2 varies from x = 0 and x = 1.
View answer & solution
Correct answer: B. 2/3
Quick explanation

Using the given constant electric-field magnitude 2 and current density J = x² over x=0 to 1, power is the integral of E·J: ∫₀¹2x²dx = 2/3.

pv = E·J P = ∫₀¹ 2x² dx = 2[x³/3]₀¹ = 2/3
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Intrinsic Impedance and Velocity (1)

Q3Moderate
Consider the following statements regarding Wave Propagation:
1. Wave impedance depends on medium properties such as permittivity and permeability.
2. In free space, intrinsic impedance is approximately 377 ohms.
3. Wave velocity depends on frequency of wave.
4. Higher permittivity reduces wave velocity.
Which of the above statements is/are correct?
View answer & solution
Correct answer: B. 1, 2 and 4 only
Quick explanation

A plane electromagnetic wave can propagate through vacuum without a material medium. In a homogeneous lossless medium, wave speed and intrinsic impedance are set by permittivity and permeability; in free space they reduce to c and about 377 ohms. Key relation: v=1/√(με); η=√(μ/ε); in free space c≈3×10^8 m/s and η0≈377 Ω.

Exam focus: Remember the orthogonal E-H-propagation triad. Common trap: In the elementary nondispersive model, wave speed is not set by frequency.

v=1/√(με); η=√(μ/ε); in free space c≈3×108 m/s and η0≈377 Ω.
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Plane EM Waves (1)

Q4Easy
Consider the following statements regarding Electromagnetic Waves:
1. Electromagnetic waves propagate in free space without requiring a material medium.
2. Electric and magnetic fields in EM wave are perpendicular to each other.
3. Wave velocity in free space is equal to speed of light.
4. EM waves cannot propagate in vacuum.
Which of the above statements is/are correct?
View answer & solution
Correct answer: A. 1, 2 and 3 only
Quick explanation

A plane electromagnetic wave can propagate through vacuum without a material medium. In a homogeneous lossless medium, wave speed and intrinsic impedance are set by permittivity and permeability; in free space they reduce to c and about 377 ohms. Key relation: v=1/√(με); η=√(μ/ε); in free space c≈3×10^8 m/s and η0≈377 Ω.

Exam focus: Remember the orthogonal E-H-propagation triad. Common trap: In the elementary nondispersive model, wave speed is not set by frequency.

v=1/√(με); η=√(μ/ε); in free space c≈3×108 m/s and η0≈377 Ω.
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Poynting Vector (1)

Q5Easy
Consider the following statements regarding Poynting Vector:
1. Poynting vector represents power flow per unit area in electromagnetic field.
2. It is given by the cross product of electric and magnetic field vectors.
3. Direction of Poynting vector indicates direction of energy propagation.
4. It has units of volts per meter.
Which of the above statements is/are correct?
View answer & solution
Correct answer: C. 1, 2 and 3 only
Quick explanation

The Poynting vector gives electromagnetic power-flow density and points in the direction of energy transport for a propagating wave. It is the cross product of electric and magnetic fields. Key relation: S=E×H [W/m²].

Exam focus: Cross E with H to get energy-flow direction. Common trap: V/m is electric-field unit, not Poynting-vector unit.

S=E×H [W/m²].
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