Electrical Engineering › Basic Electrical Engineering

AC Fundamentals MCQ [Free PDF] – 8 Objective Questions with Answers

Every AC Fundamentals question asked in GPSC DEE Electrical, GPSC AE Electrical — solve, check instantly, then read the formula and exam tip.

8 PYQs8 subtopics2 examsUpdated 23 Oct 2026
Topic practice0/8✓ 0✗ 0

Complex Power (1)

Q1Easy
Consider the following statements regarding complex power:
1. Apparent power is the magnitude of complex power.
2. Reactive power can be negative.
3. Power factor is defined as ratio of real power to reactive power.
Which of the above statements is/are correct?
View answer & solution
Correct answer: A. 1 and 2 only
Quick explanation

In sinusoidal steady state, complex power combines real and reactive power as S=P+jQ. Power factor is the ratio P/|S| and equals cosφ for sinusoidal voltage and current. Key relation: S=P+jQ; |S|=√(P²+Q²); PF=P/|S|=cosφ.

Exam focus: Draw the power triangle before choosing a power-factor relation. Common trap: Do not confuse P/Q with power factor.

S=P+jQ; |S|=√(P²+Q²); PF=P/|S|=cosφ.
Verified · SRO editorial deskSolution page → Report

Form Factor (1)

Q2Moderate
Form factor is equal to peak factor in the case of
View answer & solution
Correct answer: A. Square wave
Quick explanation

For an ideal square wave, the magnitude is constant throughout each half-cycle. Therefore peak value = rms value = average rectified value, making both peak factor and form factor equal to 1. Hence the two factors are equal for a square wave.

Vpeak = Vm Vrms = Vm Vavg,rect = Vm Peak factor = Vpeak/Vrms = 1 Form factor = Vrms/Vavg,rect = 1
Verified · SRO editorial deskSolution page → Report

Frequency and Time (1)

Q3Easy
How many cycles will an AC signal make in 2 seconds if its frequency is 100Hz?
View answer & solution
Correct answer: D. 200
Quick explanation

Frequency means cycles per second. At 100 Hz, the waveform completes 100 cycles each second; in 2 s it completes 100×2 = 200 cycles.

Number of cycles N = f t N = 100 × 2 = 200 cycles T = 1/f = 0.01 s
Verified · SRO editorial deskSolution page → Report

Peak Factor (1)

Q4Easy
Which of the following waves has the highest value of peak factor?
View answer & solution
Correct answer: C. Half wave rectified sine wave
Quick explanation

Peak factor (crest factor) is V_peak/V_rms. For a half-wave rectified sine, V_rms=V_m/2, so peak factor=2, which exceeds sine (√2), triangular (√3) and square (1).

Peak factor = Vpeak / Vrms Square = 1 Sine = √2 ≈ 1.414 Triangular = √3 ≈ 1.732 Half-wave rectified sine = 2
Verified · SRO editorial deskSolution page → Report

RMS Value (1)

Q5Easy
RMS value is defined based on which of the following?
View answer & solution
Correct answer: A. Heating effect
Quick explanation

RMS value is defined as the DC value that would produce the same heating effect in a given resistance over the same time. That is why RMS—not average or peak—is used for AC equipment voltage/current ratings.

Irms = √[(1/T)∫₀ᵀ i²(t)dt] Irms = Im/√2 PR = I_rms²R
Verified · SRO editorial deskSolution page → Report

Sinusoidal Voltage (1)

Q6Easy
An AC voltage is given by v(t) = 100 sin(ωt). Then
1. Peak voltage is 100 V.
2. RMS voltage is 100/√2.
3. RMS value ≈ 70.7 V.
4. Average value over full cycle is 100 V.
Which of the above statements is/are correct?
View answer & solution
Correct answer: C. 1, 2 and 3 only
Quick explanation

The average of a rectified sine over a half cycle is 2Xm/π, giving sine-wave form factor RMS/average-rectified ≈1.11. For v(t)=100 sinωt, Vm=100 V and Vrms=Vm/√2≈70.7 V. The full-cycle average of a sine wave is zero. Key relation: Xrms=Xm/√2; Xavg(rectified)=2Xm/π; form factor≈1.11.

Exam focus: Check whether the question asks full-cycle average or rectified average. Common trap: Using the half-cycle average as the full-cycle average is a common error.

Xrms=Xm/√2; Xavg(rectified)=2Xm/π; form factor≈1.11.
Verified · SRO editorial deskSolution page → Report

Sinusoidal Waveforms (1)

Q7Easy
Consider the following statements:
1. RMS value of sinusoidal current is its peak value divided by √2.
2. Average value of sinusoidal current over one cycle is zero.
3. Form factor of sine wave is 1.11.
Which of the above statements is/are correct?
View answer & solution
Correct answer: D. 1, 2 and 3
Quick explanation

For a sine wave x(t)=Xm sinωt, the RMS value is Xm/√2. The average of a rectified sine over a half cycle is 2Xm/π, giving sine-wave form factor RMS/average-rectified ≈1.11. Key relation: Xrms=Xm/√2; Xavg(rectified)=2Xm/π; form factor≈1.11.

Exam focus: Check whether the question asks full-cycle average or rectified average. Common trap: Using the half-cycle average as the full-cycle average is a common error.

Xrms=Xm/√2; Xavg(rectified)=2Xm/π; form factor≈1.11.
Verified · SRO editorial deskSolution page → Report

Waveform Factors (1)

Q8Easy
Which of the following is a correct representation of peak value in an AC circuit?
View answer & solution
Correct answer: D. RMS value*Peak factor
Quick explanation

Peak factor directly relates the maximum (peak) value of an AC waveform to its RMS value. By definition, Peak factor = V_peak / V_rms, so V_peak = Peak factor × V_rms. For a sine wave the peak factor is √2.

Peak factor = Vpeak / Vrms Vpeak = Peak factor × Vrms Vpeak = √2 Vrms
Verified · SRO editorial deskSolution page → Report