This question was asked inGPSC Deputy Executive Engineer (Electrical) Paper 2024Question 20 of 33 published · Gujarat Public Service CommissionOpen paper
Q71ModerateIllumination

A room is 120 feet by 60 feet with 16 feet ceiling. A luminaire is suspended 4 feet below the ceiling and the work plane is 4 feet above the floor. The value of room cavity ratio (RCR) is

Answer & step-by-step solution
Correct answer: B. 1
Quick explanation

The luminaire is 4 ft below a 16-ft ceiling and the work plane is 4 ft above the floor, so cavity height is 8 ft. Room cavity ratio is RCR=5h(L+W)/(LW). Substituting h=8 ft, L=120 ft and W=60 ft gives RCR=1.0, matching option B.

RCR=5h(L+W)/(LW)=5×8×180/(120×60)=1.0

Concept and Reasoning

The luminaire is 4 ft below a 16-ft ceiling and the work plane is 4 ft above the floor, so cavity height is 8 ft. Room cavity ratio is RCR=5h(L+W)/(LW). Substituting h=8 ft, L=120 ft and W=60 ft gives RCR=1.0, matching option B.

Calculation / Key Relation

RCR=5h(L+W)/(LW)=5×8×180/(120×60)=1.0

Exam Takeaway

Use the vertical distance from luminaire plane to work plane as cavity height.

Common Mistake

Do not use the full ceiling height as h when luminaires are suspended and a work plane is specified.

Quick Trick

Use the vertical distance from luminaire plane to work plane as cavity height.

Solution diagram – A room is 120 feet by 60 feet with 16 feet ceiling. A luminaire is suspended 4…
Exam tipUse the vertical distance from luminaire plane to work plane as cavity height.
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