How many electrons will constitute 2 Coulombs of electric charge?
Answer & step-by-step solution
Charge is quantized in units of the elementary charge e = 1.602 × 10⁻¹⁹ C. Hence n = Q/e = 2/(1.602×10⁻¹⁹) ≈ 1.248×10¹⁹ electrons = 12.48×10¹⁸ electrons.
Concept & Reasoning
Each electron carries charge magnitude e = 1.602 × 10⁻¹⁹ C. The number of electrons corresponding to a charge magnitude Q is obtained by dividing Q by e. The sign of electron charge is negative, but when a question asks 'how many electrons', the count is a positive number. Substituting Q = 2 C gives approximately 1.248 × 10¹⁹ electrons, which matches 12.48 × 10¹⁸.
How to Solve It in the Exam
1 C corresponds to about 6.24×10¹⁸ electrons; multiply by 2.
Important Exam Point
Keep scientific notation consistent before matching the option.
Quick Trick
1 C corresponds to about 6.24×10¹⁸ electrons; multiply by 2.
Common Mistake
Do not multiply Q by e; electron count is charge divided by elementary charge.
2 कूलॉम विद्युत आवेश में कितने इलेक्ट्रॉन होंगे?
उत्तर और चरणबद्ध हल
आवेश मूल आवेश e = 1.602 × 10⁻¹⁹ C की इकाइयों में क्वांटित होता है। अतः n = Q/e = 2/(1.602×10⁻¹⁹) ≈ 1.248×10¹⁹ = 12.48×10¹⁸ इलेक्ट्रॉन।
विस्तृत हल (मूल भाषा में)
Concept & Reasoning
Each electron carries charge magnitude e = 1.602 × 10⁻¹⁹ C. The number of electrons corresponding to a charge magnitude Q is obtained by dividing Q by e. The sign of electron charge is negative, but when a question asks 'how many electrons', the count is a positive number. Substituting Q = 2 C gives approximately 1.248 × 10¹⁹ electrons, which matches 12.48 × 10¹⁸.
How to Solve It in the Exam
1 C corresponds to about 6.24×10¹⁸ electrons; multiply by 2.
Important Exam Point
Keep scientific notation consistent before matching the option.
Quick Trick
1 C corresponds to about 6.24×10¹⁸ electrons; multiply by 2.
Common Mistake
Do not multiply Q by e; electron count is charge divided by elementary charge.
2 કુલંબ વિદ્યુતભારમાં કેટલા ઇલેક્ટ્રોન હશે?
જવાબ અને પગલાવાર ઉકેલ
વિદ્યુતભાર મૂળભૂત વિદ્યુતભાર e = 1.602 × 10⁻¹⁹ C ના એકમોમાં ક્વોન્ટાઇઝ્ડ હોય છે. તેથી n = Q/e = 2/(1.602×10⁻¹⁹) ≈ 1.248×10¹⁹ = 12.48×10¹⁸ ઇલેક્ટ્રોન.
વિગતવાર ઉકેલ (મૂળ ભાષામાં)
Concept & Reasoning
Each electron carries charge magnitude e = 1.602 × 10⁻¹⁹ C. The number of electrons corresponding to a charge magnitude Q is obtained by dividing Q by e. The sign of electron charge is negative, but when a question asks 'how many electrons', the count is a positive number. Substituting Q = 2 C gives approximately 1.248 × 10¹⁹ electrons, which matches 12.48 × 10¹⁸.
How to Solve It in the Exam
1 C corresponds to about 6.24×10¹⁸ electrons; multiply by 2.
Important Exam Point
Keep scientific notation consistent before matching the option.
Quick Trick
1 C corresponds to about 6.24×10¹⁸ electrons; multiply by 2.
Common Mistake
Do not multiply Q by e; electron count is charge divided by elementary charge.
More Basic Concepts questions