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MediumDeputy Executive Engineer (Electrical), Class-2, Sports Authority of Gujarat / Assistant Engineer (Electrical), Class-2,2026✓ Editorially verified
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A unity feedback system has open-loop transfer function such that it is a type-1 system and subjected to a unit step input, then1.The steady-state error for step input is zero.2.The steady-state error for ramp input is finite.3.Increasing system gain reduces steady-state error for ramp input.4.The steady-state error for step input increases with increase in gain.Which of the above statements is/are correct?

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Answer & Explanation
Correct AnswerA. 1, 2 and 3 only

Quick Explanation

It determines the order of polynomial input that can be tracked with zero/finite/infinite steady-state error, provided the closed loop is stable. Static-error constants directly produce the truth set {1,2,3}. Key relation: Type 1: Kp=lim_{s→0}GH=∞ → ess,step=1/(1+Kp)=0; Kv=lim_{s→0}sGH finite → ess,ramp=1/Kv.

Exam focus: Type-1 mnemonic: step → zero error; ramp → finite error; parabolic → infinite error. Common trap: Ignoring the closed-loop stability condition when applying steady-state error formulas.

Formula / Key Relation

Type 1: Kp=lim_{s→0}GH=∞ → ess,step=1/(1+Kp)=0; Kv=lim_{s→0}sGH finite → ess,ramp=1/Kv.

Detailed Explanation

Correct Answer: A - 1, 2 and 3 only Quick Concept Explanation It determines the order of polynomial input that can be tracked with zero/finite/infinite steady-state error, provided the closed loop is stable. Static-error constants directly produce the truth set {1,2,3}. Key relation: Type 1: Kp=lim_{s→0}GH=∞ → ess,step=1/(1+Kp)=0; Kv=lim_{s→0}sGH finite → ess,ramp=1/Kv.Exam focus: Type-1 mnemonic: step → zero error; ramp → finite error; parabolic → infinite error. Common trap: Ignoring the closed-loop stability condition when applying steady-state error formulas. Statement-wise Verification Statement 1 - Correct.The steady-state error for step input is zero.One integrator makes the position constant Kp infinite, so…

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