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HardDeputy Executive Engineer (Electrical), Class-2, Sports Authority of Gujarat / Assistant Engineer (Electrical), Class-2,2026✓ Editorially verified
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A single-phase full-bridge VSI is fed from a 48 V battery and delivers power to a resistive load of 10 Ω. Using square wave switching, verify1.RMS value of fundamental output voltage is 43.2 V.2.Power delivered by the fundamental component is 186.6 W.3.Total power delivered to the load is 230.4 W.Which of the statements are correct?

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Answer & Explanation
Correct AnswerD. 1, 2 and 3

Quick Explanation

In 180° conduction, three devices conduct at a time and the fundamental output is higher; the floating star neutral can shift relative to the DC midpoint. Full-bridge square-wave total RMS voltage is 48 V, so total load power=48²/10=230.4 W. Fundamental RMS=4Vdc/(π√2)≈43.2 V and fundamental power≈43.2²/10=186.6 W.

Exam focus: Track pole voltage and load-neutral voltage separately. Common trap: Balanced load does not force the floating neutral to the DC midpoint at every switching state.

Formula / Key Relation

Conduction duration: 120°→two switches at a time; 180°→three switches at a time.

Detailed Explanation

Correct Answer: D - 1, 2 and 3 Quick Concept Explanation In 180° conduction, three devices conduct at a time and the fundamental output is higher; the floating star neutral can shift relative to the DC midpoint. Full-bridge square-wave total RMS voltage is 48 V, so total load power=48²/10=230.4 W. Fundamental RMS=4Vdc/(π√2)≈43.2 V and fundamental power≈43.2²/10=186.6 W.Exam focus: Track pole voltage and load-neutral voltage separately. Common trap: Balanced load does not force the floating neutral to the DC midpoint at every switching state. Statement-wise Verification Statement 1 - Correct.RMS value of fundamental output voltage is 43.2 V.Fundamental RMS=4Vdc/(π√2)≈43.2 V and…

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