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HardDeputy Executive Engineer (Electrical), Class-2, Sports Authority of Gujarat / Assistant Engineer (Electrical), Class-2,2026✓ Editorially verified
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A fault occuring at the terminals of an unloaded synchronous generator operating at its rated voltage has resulted in the following values of currents and voltages:Ia0 = j2.37 p.u.Ia1 = – j3.05 p.u.Ia2 = j0.68 p.u.Va0 = Va1 = Va2 = 0.237 p.u.Which one of the following faults has occurred?

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Answer & Explanation
Correct AnswerB. L - L - G fault

Quick Explanation

For a double-line-to-ground fault on phases b and c, the unfaulted phase current Ia is zero and the fault-point sequence voltages satisfy the appropriate equal-voltage relation. Three independent signatures agree: zero sequence present → ground fault; Ia=0 → phase a healthy; negative sequence present → unbalanced two-phase involvement.

Exam focus: Fault ID shortcut: zero-sequence present means the ground path participates. Common trap: Selecting a 3-phase fault despite nonzero I0 and I2.

Formula / Key Relation

Ia=I0+I1+I2. Here Ia=0. Phase transformation: [Va Vb Vc]^T = A[V0 V1 V2]^T.

Detailed Explanation

Correct Answer: B - L - L - G fault Quick Concept Explanation For a double-line-to-ground fault on phases b and c, the unfaulted phase current Ia is zero and the fault-point sequence voltages satisfy the appropriate equal-voltage relation. Three independent signatures agree: zero sequence present → ground fault; Ia=0 → phase a healthy; negative sequence present → unbalanced two-phase involvement.Exam focus: Fault ID shortcut: zero-sequence present means the ground path participates. Common trap: Selecting a 3-phase fault despite nonzero I0 and I2. Technical Verification Given V0=V1=V2=0.237 p.u. This equality is compatible with the boundary condition for a double-line-to-ground fault…

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