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When a stack segment is initialised, then

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Answer & Explanation

Correct AnswerA. SS and SP are initialised

Quick Explanation

A usable 8086 stack requires both SS (Stack Segment) and SP (Stack Pointer) to be initialized. SS identifies the stack segment base and SP gives the offset of the current top of stack.

Formula / Key Relation

Physical address = 16×SS + SP

Detailed Explanation

Concept & Reasoning

Physical stack addresses are formed from SS:SP. PUSH, POP, CALL, RET and interrupt operations automatically update SP, usually by two bytes for 16-bit words. If either SS or SP is undefined, stack accesses may go to an unintended memory location.

How to Solve It in the Exam

Stack address always think SS:SP pair.

Important Exam Point

Initialize SS and SP coherently before enabling operations that may use the stack.

Related Revision Path

This question sits in the revision path Microprocessors and Interfacing → 8086 Microprocessor → Memory Segmentation .

Stack Segment Initialization explanatory diagram

Quick Trick

Stack address always think SS:SP pair.

Common Mistake

Initializing only SS and assuming SP automatically points to a valid stack top.

Exam Tip

Initialize SS and SP coherently before enabling operations that may use the stack.

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Exam Path

Knowledge Path

Study concept · Stack Segment Initialization →Practice concept Practice topic

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