A ±200 kV bipolar HVDC system has one pole at +200 kV and the other at −200 kV with respect to ground. Therefore the pole-to-pole transmission voltage is 200 − (−200) = 400 kV.
Formula / Key Relation
Vpole-to-pole = (+200 kV) − (−200 kV)
= 400 kV
Detailed Explanation
Concept & Reasoning
The ± notation gives each pole's voltage relative to earth/neutral. In a bipolar scheme the useful voltage between conductors is twice the pole-to-ground magnitude. The MW rating is not needed to calculate this voltage.
How to Solve It in the Exam
±V bipolar link → conductor-to-conductor voltage = 2V.
Important Exam Point
Separate pole voltage from pole-to-pole transmission voltage.
Related Revision Path
This question sits in the revision path Power Electronics → HVDC Transmission → Bipolar HVDC .
Quick Trick
±V bipolar link → conductor-to-conductor voltage = 2V.
Common Mistake
Reporting 200 kV because each individual pole is rated 200 kV to ground.
Exam Tip
Separate pole voltage from pole-to-pole transmission voltage.
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