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Three charged cylindrical sheets are present in three spaces with σ = 5 at R = 2m, σ = − 2 at R = 4m and σ = − 3 at R = 5m. Find the flux density at R = 3m.

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Answer & Explanation
Correct AnswerB. 10/3

Quick Explanation

At r = 3 m only the cylindrical sheet at r = 2 m is enclosed; the sheets at 4 m and 5 m lie outside. Gauss' law gives D(r) = σa/r = 5×2/3 = 10/3 in the radial direction.

Formula / Key Relation

D(2πrL) = σ(2πaL)
D = σa/r
= 5×2/3
= 10/3

Detailed Explanation

Concept & ReasoningChoose a coaxial Gaussian cylinder of radius r=3 m and length L. The enclosed charge is σ(2πaL) from the sheet at a=2 m. The outer charged sheets do not contribute to enclosed charge at this Gaussian radius. By symmetry D is radial and constant on the cylindrical Gaussian surface, so D(2πrL)=σ(2πaL), yielding D=σa/r=10/3. This is a direct application of Gauss' law for an infinite cylindrical sheet.How to Solve It in the ExamFor concentric sheets, include only charges with radius less than the observation radius.Important Exam PointList enclosed sheets before writing Gauss' law.Related Revision PathThis question sits in the…

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Assistant Engineer (Electrical), Class-2, Road and Building Department2025Q. 144
Assistant Engineer (Electrical), Class-2, Road and Building Department2025Q. 144
Assistant Engineer (Electrical), Class-2, Road and Building Department2025Q. 144
Assistant Engineer (Electrical), Class-2, Road and Building Department2025Q. 144
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Assistant Engineer (Electrical), Class-2, Road and Building Department2025Q. 144
Assistant Engineer (Electrical), Class-2, Road and Building Department2025Q. 144
Assistant Engineer (Electrical), Class-2, Road and Building Department2025Q. 144
Assistant Engineer (Electrical), Class-2, Road and Building Department2025Q. 144

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