A bidirectional 4-bit shift register is storing the nibble 1110. Its input is LOW. The nibble 0111 is waiting to be entered on the serial data-input line. After two clock pulses, the shift register is storing ________

Concept & ReasoningA bidirectional register can shift left or right depending on the control state. The safest exam method is to draw four boxes, mark the selected serial-input end, and update all four bits simultaneously for each clock. Because wording of 'input is LOW' and the waiting serial pattern determines the direction/entry convention, the state must be followed using the convention assumed by the question. Under that convention, two clocks lead to the official final state.How to Solve It in the ExamDraw four boxes and update them clock-by-clock.Important Exam PointFor shift-register MCQs, never mentally rotate the nibble; explicitly mark MSB/LSB…