Consider the following statements regarding Power Factor improvement:1.Improving the power factor reduces the kVA demand of the plant.2.Capacitors should be installed as close to the inductive load as possible to reduce line losses.3.A high power factor increases the current flowing through the transmission lines for the same kW load.Which of the statements given above is/are correct?
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For a fixed real-power load and supply voltage, poor power factor requires higher current. Raising power factor with shunt capacitors or an over-excited synchronous machine reduces kVA demand, line current and I²R losses and generally improves voltage regulation. Key relation: Single phase: I=P/(V·PF). Three phase: I=P/(√3 V_L·PF).
Exam focus: For the same kW, current is inversely proportional to power factor. Common trap: Capacitors supply leading reactive power; they do not supply lagging VARs.
Formula / Key Relation
Single phase: I=P/(V·PF). Three phase: I=P/(√3 VL·PF).
Detailed Explanation
Correct Answer: A - 1 and 2 only Quick Concept Explanation For a fixed real-power load and supply voltage, poor power factor requires higher current. Raising power factor with shunt capacitors or an over-excited synchronous machine reduces kVA demand, line current and I²R losses and generally improves voltage regulation. Key relation: Single phase: I=P/(V·PF). Three phase: I=P/(√3 V_L·PF).Exam focus: For the same kW, current is inversely proportional to power factor. Common trap: Capacitors supply leading reactive power; they do not supply lagging VARs. Statement-wise Verification Statement 1 - Correct.Improving the power factor reduces the kVA demand of the plant.Raising power…
Correct Answer: A - 1 and 2 only
Quick Concept Explanation
For a fixed real-power load and supply voltage, poor power factor requires higher current. Raising power factor with shunt capacitors or an over-excited synchronous machine reduces kVA demand, line current and I²R losses and generally improves voltage regulation. Key relation: Single phase: I=P/(V·PF). Three phase: I=P/(√3 V_L·PF).
Exam focus: For the same kW, current is inversely proportional to power factor. Common trap: Capacitors supply leading reactive power; they do not supply lagging VARs.
Statement-wise Verification
Statement 1 - Correct. Improving the power factor reduces the kVA demand of the plant. Raising power factor with shunt capacitors or an over-excited synchronous machine reduces kVA demand, line current and I²R losses and generally improves voltage regulation.
Statement 2 - Correct. Capacitors should be installed as close to the inductive load as possible to reduce line losses. Compensation should be placed close to the inductive load when practical so reactive current does not travel through upstream conductors.
Statement 3 - Incorrect. A high power factor increases the current flowing through the transmission lines for the same kW load. For fixed kW and voltage, higher power factor reduces current
Core Concept
For a fixed real-power load and supply voltage, poor power factor requires higher current. Raising power factor with shunt capacitors or an over-excited synchronous machine reduces kVA demand, line current and I²R losses and generally improves voltage regulation. Compensation should be placed close to the inductive load when practical so reactive current does not travel through upstream conductors.
Formula / Key Relationship
Single phase: I=P/(V·PF). Three phase: I=P/(√3 V_L·PF).
Why the Other Options Are Wrong
Option B is incorrect because it includes incorrect statement(s) 3 and omits correct statement(s) 1. Option C is incorrect because it includes incorrect statement(s) 3 and omits correct statement(s) 1, 2. Option D is incorrect because it includes incorrect statement(s) 3.
Exam Shortcut / Approach
For the same kW, current is inversely proportional to power factor.
Common Mistake
Capacitors supply leading reactive power; they do not supply lagging VARs.
Quick Revision
kVA Demand Capacitor Location and Line Current is linked with Power Factor Improvement, Electrical Energy Efficiency and Energy Management. For the same kW, current is inversely proportional to power factor.
Quick Trick
For the same kW, current is inversely proportional to power factor.
Why Other Options Are Wrong
Option B is incorrect because it includes incorrect statement(s) 3 and omits correct statement(s) 1. Option C is incorrect because it includes incorrect statement(s) 3 and omits correct statement(s) 1, 2. Option D is incorrect because it includes incorrect statement(s) 3.
Common Mistake
Capacitors supply leading reactive power; they do not supply lagging VARs.
Exam Tip
For the same kW, current is inversely proportional to power factor.
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