SarkariResultOutBMS · 2024

Previous Year Question

The Nyquist rate for the signal x(t) = [1 + cos(2000πt) + sin(4000πt)] is
  1. 4000
  2. 8000
  3. 8000π
  4. 4000π dx(t)

Correct answer: A

Explanation

cos(2000πt) has frequency 1000 Hz and sin(4000πt) has frequency 2000 Hz because ω=2πf. The highest frequency is therefore 2000 Hz, so the Nyquist rate is 2fmax=4000 samples/s. Hence option A.

Formula

fmax=4000π/(2π)=2000 Hz; fs,Nyquist=2fmax=4000 samples/s

Step-by-step solution

Multi-Tone Nyquist Rate explanatory diagram

Correct Answer

A — 4000

Concept and Reasoning

cos(2000πt) has frequency 1000 Hz and sin(4000πt) has frequency 2000 Hz because ω=2πf. The highest frequency is therefore 2000 Hz, so the Nyquist rate is 2fmax=4000 samples/s. Hence option A.

Calculation / Key Relation

fmax=4000π/(2π)=2000 Hz

fs,Nyquist=2fmax=4000 samples/s

Exam Takeaway

Convert angular frequency to hertz before doubling.

Common Mistake

Do not treat the coefficient 4000π as frequency in hertz.

Common mistake

Do not treat the coefficient 4000π as frequency in hertz.

Exam tip

Convert angular frequency to hertz before doubling.

Quick method

Convert angular frequency to hertz before doubling.