SarkariResultOutBMS · 2024

Previous Year Question

An LTI system having transfer function G(s) = 10/(s + 5) is controlled by a proportional controller with a gain of Kp = 2. Consider the unity feedback system. Find the steady state error of the closed loop system, if the reference signal is a step input with a magnitude of 5.
  1. 1
  2. 0.8
  3. 0.2
  4. 0

Correct answer: A

Explanation

With proportional gain Kp=2, the forward path is 20/(s+5). The position error constant is Kp0=lim GOL(s)=4. For a step of magnitude 5, ess=5/(1+4)=1.

Formula

Kp0=limₛ→0 20/(s+5)=4; ess=A/(1+Kp0)=5/5=1

Step-by-step solution

Step Steady-State Error explanatory diagram

Correct Answer

A — 1

Concept and Reasoning

With proportional gain Kp=2, the forward path is 20/(s+5). The position error constant is Kp0=lim GOL(s)=4. For a step of magnitude 5, ess=5/(1+4)=1.

Calculation / Key Relation

Kp0=limₛ→0 20/(s+5)=4

ess=A/(1+Kp0)=5/5=1

Exam Takeaway

For a type-0 unity-feedback system, step error is A/(1+Kp0).

Common Mistake

Do not use the controller gain alone as the position error constant.

Common mistake

Do not use the controller gain alone as the position error constant.

Exam tip

For a type-0 unity-feedback system, step error is A/(1+Kp0).

Quick method

For a type-0 unity-feedback system, step error is A/(1+Kp0).